All categories

3 years ago

Can anyone help with this question please!

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

6 0

Answer:

6 in

Step-by-step explanation:

A= bh

18 as our area= 3 as our base and (x) as the height

18/3 = 6

so 6 is the height

Let's make sure that the answer is right:

A= bh

A= 3(6)

A= 18

You might be interested in

In the diagram below, we have ST parallel to QR. angle P= 40 degrees, and angle Q= 35 degrees. Find the measure of angles STR in

Drupady [299]

Answer:

$m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ$

Step-by-step explanation:

<u>Similar Triangles</u>

Lines ST and QR are parallel. Thus, angles S and Q are congruent, and angles T and R are congruent.

Considering the triangle PQR, the sum of its internal angles must be 180°:

$m\angle P + m\angle Q + m\angle R = 180^\circ$

Substituting the known values:

$40^\circ + 35^\circ + m\angle R = 180^\circ$

Solving for R:

$m\angle R = 180^\circ - 40^\circ - 35^\circ$

$m\angle R = 105^\circ$

Angles S and Q are congruent, thus

$m\angle S = 35^\circ$

Angles T and R are congruent, thus

$m\angle T = 105^\circ$

Summarizing:

$\mathbf{m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ}$

7 0

3 years ago

Read 2 more answers

cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta

NikAS [45]

First calculate $\sin\theta$ .

$\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}$

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

$\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\
\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}$

5 0

2 years ago

Read 2 more answers

HELP is 3.31227766... a rational OR irrational number?

laila [671]

Answer:

irrational

hope this helps

have a good day :)

Step-by-step explanation:

8 0

2 years ago