All categories

3 years ago

Can anyone help with this question please!

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

6 0

Answer:

6 in

Step-by-step explanation:

A= bh

18 as our area= 3 as our base and (x) as the height

18/3 = 6

so 6 is the height

Let's make sure that the answer is right:

A= bh

A= 3(6)

A= 18

You might be interested in

What is 9+5x-5+3x? What could it be

qwelly [4]

8x+4 would be the answer if you combine like terms

6 0

3 years ago

What is the inverse function for h(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-1" id="TexFormula1" title="\sqrt

Blizzard [7]

Step-by-step explanation:

$y = \sqrt{x + 7} - 1$

Replace x and y.

$x = \sqrt{y + 7} - 1$

Solve for y.

$x + 1 = \sqrt{y + 7}$

Square both sides.

$(x + 1) {}^{2} = y + 7$

$(x + 1) {}^{2} - 7 = y$

This is the inverse function or you can also say

${x}^{2} + 2x - 6 = y$

5 0

3 years ago

Find the range y=4-x domain =-2,3,5

Wittaler [7]

Answer:

range: {6, 1, -1}

Step-by-step explanation:

y = 4-x

when x = -2, y = 6

when x = 3, y = 1

when x = 5, y = -1

6 0

3 years ago

Please help I do not know how to do this

stepan [7]

Answer:

∠ b = 23°

Step-by-step explanation:

Complementary angles sum to 90° , then

a + b = 90° , that is

67° + b = 90° ( subtract 67° from both sides )

∠ b = 23°

3 0

3 years ago

Read 2 more answers

A^2(64a^2-3)/3=27-4a^2/4

frutty [35]

The answer is a = 3/4 = 0.75

First get rid of the paranthesis,
${a}^{2} (64 {a}^{2} - 3) = 64 {a}^{4} - 3 {a}^{2}$
Then set the denominators equal:
$\frac{ 256 {a}^{4} - 12 {a}^{2}}{12} = \frac{81 - 12 {a}^{2} }{12}$
Then remove the denominators and solve:
$256 {a}^{4} - 12 {a}^{2} = 81 - 12 {a}^{2}$
Eliminate -12a^2 by adding 12a^2 to both sides:
$256 {a}^{4} = 81$
Take the fourth root of them or take the square root twice:
$\sqrt[4]{256 {a}^{4} } = \sqrt[4]{81} \\ 4a = 3$
Divide both sides by 4:
$a = \frac{3}{4} = 0.75$

7 0

3 years ago