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nata0808 [166]
3 years ago
6

What Is the least common demonitor of 25 and 75

Mathematics
2 answers:
cluponka [151]3 years ago
7 0

Answer:

3

Step-by-step explanation:

3

Oxana [17]3 years ago
4 0
1/3 because when you divide both by 25 you get that answer
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In one month, Juan worked 5 more hours than Carlito. Sara worked 3 times as many hours as Juan. Altogether they worked 80 hours
tamaranim1 [39]

Answer:

The answer to your question is  a) C + J + S = 80

                                                     b) C = J + 5

                                                      c) S = 45 hours

Step-by-step explanation:

a) To represent the number of hours that they work together, just add the variables and equal them to 80.

            Carlito  +  Juan  +  Sara  = 80

               C + J + S = 80                                 Equation l

b) Juan worked 5 hours more than Carlito

              Juan = Carlito + 5

                  J = C  + 5                                     Equation ll

c) Hours worked by Sara

                  S = 3J                                          Equation lll

                  C = J - 5

Substitute equation ll and lll in equation l to find J

                J - 5 + J + 3J = 80

                5J = 80 - 5

                5J = 75

                  J = 75/5

                  J = 15

-Find S

                S = 3(15)

                S = 45 hours

3 0
4 years ago
Read 2 more answers
Select the best answer.<br><br> tan x tan x/2=
Colt1911 [192]
Tan 2 x-2 tan x=0
Tan x (tan x-2 ) =0
A tan x=0 —> x=0 and x =K π
B tan x=2 —> x=63.43 +k180 deg

4 0
3 years ago
What is the correct answer and can someone please explain how they found the answer? Thank you
STatiana [176]
7480 Hope this helps
3 0
3 years ago
Help again...its for math offering 15 points
Anettt [7]

Answer:

\tan \dfrac{\theta}2 = \dfrac{1}2

Step by step Explanation:

\sin \theta = \dfrac{\text{Perpendicular} }{\text{Hypotenuse}} = \dfrac{12}{15}\\\\\\\cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}= \dfrac{9}{15}\\\\\text{Now,}\\\\\tan \dfrac{\theta}2 = \dfrac{\sin \tfrac{\theta}2}{\cos \tfrac{\theta}2}\\\\\\~~~~~~~~=\dfrac{2\cos \tfrac{\theta}2 \sin \tfrac{\theta}2 }{2\cos^2 \tfrac{\theta}2}~~~~~~;\left[\text{Multiply by}~ 2\cos\tfrac{\theta}2 \right]

         =\dfrac{\sin \theta}{1+ \cos \theta}~~~~~~~~~~~~;[2 \sin x \cos x = \sin 2x ~ \text{and}~ 2\cos^2 x =1+\cos 2x]\\\\\\=\dfrac{\tfrac{12}{15}}{1+ \tfrac{9}{15}}\\\\\\=\dfrac{\tfrac{12}{15}}{\tfrac{24}{15}}\\\\\\=\dfrac{12}{15}\times \dfrac{15}{24}\\\\\\=\dfrac{12}{24}\\\\\\=\dfrac{1}2

4 0
2 years ago
| 10x + 10 | – 2 = 78
mr Goodwill [35]
The answer should be

x = 7 or just 7

Hope it helped !!
6 0
4 years ago
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