Put the values in order of least to greatest, and then eliminate numbers from each end until you’re left with one.
79, 82, 87, 91, 93, 97, 97, 98, 99, 101, 102
Median - Middle number, 97
Mode - Number that appears most often, 97
Mean - Add all numbers and then divide the total by the number of values in the data set, 93.3
Answer:
(A) 30772cm^2/s
(B) 153860cm^2/s
(C) 184632 cm^2/s
Step-by-step explanation:
We are given
speed of the ripple = 70cm/s
this speed is increasing the radius which means speed = radius /time
radius = speed*time
r= 70t
Now we know the area of the circle
A = π
this area will be increasing as ripples in water will spread out
upon differentiating
dA/dt = 2πr * 
dA/dt = 2π*70t*70 ( r= 70t , dr/dt = speed = 70)
dA/dt = 9800π*t
(A) after 1 second
dA/dt = 9800π*1=9800π = 30772cm^2/s
(B) after 5 seconds
dA/dt = 9800π*5 = 153860cm^2/s
(C) after 6 seconds
dA/dt = 9800π*6 = 184632 cm^2/s
Step-by-step explanation:
In ∆ABC, if <A is 90° and <B is 45° then hypotenuse is BC.
Now,
Cos B= base/height
Cos B= AB/ BC
BC= AB/cos 45°.
Answer:
D
Step-by-step explanation:
I had a test and this is the answer. :)
<h3>
Answer: -0.196</h3>
======================================================
Explanation:
We're conducting a one proportion Z test.
The hypothesized population proportion is p = 0.53, which is not to be confused with the p-value (unfortunately statistics textbooks seem to overuse the letter 'p'). Luckily this problem is not asking for the p-value.
The sample population proportion is
phat = x/n = 41/79 = 0.518987 approximately
The standard error (SE) is
SE = sqrt(p*(1-p)/n)
SE = sqrt(0.53*(1-0.53)/79)
SE = 0.056153 approximately
Making the test statistic to be
z = (phat - p)/(SE)
z = (0.518987 - 0.53)/0.056153
z = -0.19612487311452
z = -0.196
Which is approximate and rounded to 3 decimal places.
