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3 years ago

I need help with a Algebra 2 question. MESSAGE ME IF YOU CAN HELP ME PLEASEEEE .

Mathematics

1 answer:

Marina CMI [18]3 years ago

6 0

Hey! I'm in Algebra 2 right now, so I think I can help!

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Help I'll give you 100 points

Dvinal [7]

✏ Answer:

$y=-9$

Step-by-step explanation:

$2-\frac{1}{8}y=11+\frac{7}{8}y$

➠ Subtract 2 from both sides:-

 $2-\frac{1}{8}y-2=11+\frac{7}{8}y-2$

$-\frac{1}{8}y=\frac{7}{8}y+9$

➠ Subtract 7/8y from both sides:-

 $-\frac{1}{8}y-\frac{7}{8}y=\frac{7}{8}y+9-\frac{7}{8}y$

$-y=9$

➠ Divide both sides by -1:-

 $\frac{-y}{-1}=\frac{9}{-1}$

$y=-9$

OAmalOHopeO

✎--------------------------

7 0

3 years ago

Read 2 more answers

What is the best way to determine the graph of a situation?

elixir [45]

Answer:

iys answer can be

by drawing

3 0

3 years ago

#3 Can someone please help me with these questions!!!!

rosijanka [135]

Answer:

Option A 90,68

$m\angle 1=90^o$

$m\angle 2=68^o$

Step-by-step explanation:

see the attached figure to better understand the problem

The figure shows a kite

we know that

A kite properties include

1) two pairs of consecutive, congruent sides

2) congruent non-vertex angles

3) perpendicular diagonals

Find the measure of angle 1

we have that

$m\angle 1=90^o$ ----> by the diagonals are perpendicular

Find the measure of angle 2

we know that

triangle AEB is congruent with triangle CEB

$m\angle EAB=m\angle ECB=m\angle 2$

In the right triangle EAB

$m\angle EAB+22^o=90^o$ ----> by complementary angles in a right triangle

$m\angle EAB=90^o-22^o=68^o$

therefore

$m\angle 2=68^o$

7 0

3 years ago

A venue plans to host trucking events regularly throughout the year. The expected revenue from each event is $100,000. The cost

iris [78.8K]

Answer:

The venue has to host 47 events throughout the year

Step-by-step explanation:

Profit:

Profit is revenue subtracted by costs.

Per event:

$100,000 revenue

$50,000 costs

$100,000 - $50,000 = $50,000 profit.

If the venue wants to make a total profit margin of $2,350,000, how many events does the venue have to host throughout the year?

1 event - $50,000 profit.

x events - $2,350,000 profit.

$50000x = 2350000$

$x = \frac{2350000}{50000}$

$x = 47$

The venue has to host 47 events throughout the year

6 0

3 years ago

Round 2.56×0.03 to the nearest hundredth

Arlecino [84]

2.56 times 0.03 is 0.0768 then round to hundredth is 0.08 i think

4 0

4 years ago