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andrey2020 [161]
3 years ago
14

I need help with a Algebra 2 question. MESSAGE ME IF YOU CAN HELP ME PLEASEEEE .

Mathematics
1 answer:
Marina CMI [18]3 years ago
6 0

Hey! I'm in Algebra 2 right now, so I think I can help!


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Help I'll give you 100 points
Dvinal [7]

✏ Answer:

y=-9

Step-by-step explanation:

2-\frac{1}{8}y=11+\frac{7}{8}y

<u>➠</u><u> Subtract 2 from both sides:-</u>

<u />2-\frac{1}{8}y-2=11+\frac{7}{8}y-2

-\frac{1}{8}y=\frac{7}{8}y+9

<u>➠</u><u> Subtract 7/8y  from both sides:-</u>

<u />-\frac{1}{8}y-\frac{7}{8}y=\frac{7}{8}y+9-\frac{7}{8}y

-y=9

<u>➠</u><u> Divide both sides by -1:-</u>

<u />\frac{-y}{-1}=\frac{9}{-1}

y=-9

<u>OAmalOHopeO</u>

<u>✎--------------------------</u>

7 0
3 years ago
Read 2 more answers
What is the best way to determine the graph of a situation?
elixir [45]

Answer:

iys answer can be

by drawing

3 0
3 years ago
#3 Can someone please help me with these questions!!!!
rosijanka [135]

Answer:

Option A 90,68

m\angle 1=90^o

m\angle 2=68^o

Step-by-step explanation:

see the attached figure to better understand the problem

The figure shows a kite

we know that

A kite properties include

1) two pairs of consecutive, congruent sides

2) congruent non-vertex angles

3) perpendicular diagonals

Find the measure of angle 1

we have that

m\angle 1=90^o ----> by the diagonals are perpendicular

Find the measure of angle 2

we know that

triangle AEB is congruent with triangle CEB

so

m\angle EAB=m\angle ECB=m\angle 2

In the right triangle EAB

m\angle EAB+22^o=90^o ----> by complementary angles in a right triangle

so

m\angle EAB=90^o-22^o=68^o

therefore

m\angle 2=68^o

7 0
3 years ago
A venue plans to host trucking events regularly throughout the year. The expected revenue from each event is $100,000. The cost
iris [78.8K]

Answer:

The venue has to host 47 events throughout the year

Step-by-step explanation:

Profit:

Profit is revenue subtracted by costs.

Per event:

$100,000 revenue

$50,000 costs

$100,000 - $50,000 = $50,000 profit.

If the venue wants to make a total profit margin of $2,350,000, how many events does the venue have to host throughout the year?

1 event - $50,000 profit.

x events - $2,350,000 profit.

50000x = 2350000

x = \frac{2350000}{50000}

x = 47

The venue has to host 47 events throughout the year

6 0
3 years ago
Round 2.56×0.03 to the nearest hundredth
Arlecino [84]
2.56 times 0.03 is 0.0768 then round to hundredth is 0.08 i think 
4 0
4 years ago
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