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lukranit [14]
2 years ago
13

Please help me!!! I don't understand this at all

Mathematics
2 answers:
tia_tia [17]2 years ago
7 0

Answer:

16y

8y

Step-by-step explanation:

Firstly you would times the numbers, then you have a look at the algebraic notation and then add "y" at the end of the numbers

so it would be 2 x 8 = 16 x Y = 16y

Y doesnt have a value of a number it will stay a letter

You could say the value of y is 1 so 16 x 1 = 16 but it would be 16y

Please mark brainliest!

Hope this helped!!

Varvara68 [4.7K]2 years ago
3 0
<h2>a) 16y</h2><h2>b) 8y</h2>

a) First, multiply the numbers 8 and 2, and we get 16.

Now, we have to multiply 16 and the algebraic notation “y”, we get the result of 16y.

<h3><u>Whenever you multiply the number(s) with algebraic notations, you need to multiply the number(s) and write the algebraic notation at the end.</u></h3>

<u></u>

b) Multiply the number 8 and the algebraic notation “y”, and we get the result 8y.

<em>Hope this helps :)</em>

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\bf (\stackrel{x_1}{14}~,~\stackrel{y_1}{-8})\qquad (\stackrel{x_2}{24}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{(-8)}}}{\underset{run} {\underset{x_2}{24}-\underset{x_1}{14}}}\implies \cfrac{-3+8}{10}\implies \cfrac{5}{10}\implies \cfrac{1}{2}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-8)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{14}) \\\\\\ y+8=\cfrac{1}{2}x-7\implies y=\cfrac{1}{2}x-15

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3 years ago
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10) Use the equation x2 + 8x = 9 to answer the following questions (1 point for each part, 2 points total). .
GREYUIT [131]

Answer:

i might be wrong but i think its 10

Step-by-step explanation:

x2+8x=9

collet terms

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alternative form

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8 0
3 years ago
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Harlamova29_29 [7]
<h3>#End behaviour:-</h3>

#1

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#2

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Find nodes

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#2

It's a parabola so it's the graph of a quadratic equation.

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2 years ago
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