Answer:
£ 6,564.70
Step-by-step explanation:
Henry places £6000 in an account which pays 4.6% compound interest each year. Calculate the amount in his amount after 2 years
Compound Interest formula =
A = P(1 + r/n)^nt
A = Final Amounrt
P = Principal = £6,000
r = Interest rate = 4.6%
t = Time in years = 2 years
n = Compounding frequency = Yearly = 1
First, convert R percent to r a decimal
r = R/100
r = 4.6%/100
r = 0.046 per year,
Then, solve our equation for A
A = P(1 + r/n)^nt
A = 6,000.00(1 + 0.046/1)^(1×2)
A = £ 6,564.70
The amount in his account after 2 years = £ 6,564.70
Answer:
144322221111155554444444333222222
<em>Hi there!</em>
<em>This should be easy,lol!</em>
<em>Answer:</em>
<em />![\sqrt[3]{-128} = \boxed{-128 \sqrt{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-128%7D%20%3D%20%5Cboxed%7B-128%20%5Csqrt%7B3%7D%20%7D)
<em> (Decimal: -221.702503)</em>
<em />![\sqrt[3]{162} = \boxed{162 \sqrt{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162%7D%20%3D%20%5Cboxed%7B162%20%5Csqrt%7B3%7D%20%7D)
<em> (Decimal: 280.592231)</em>
<em />![\sqrt[3]{-1000x^4} = \boxed{-1732.050808x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1000x%5E4%7D%20%3D%20%5Cboxed%7B-1732.050808x%5E4%7D)
<em />
<em>Sorry bout the explanation thingy. Their really long -.-!</em>
<em>But the last one is short so i'll put it for you!</em>
<em>Step-by-step explanation:</em>
<em>∴!For the last one!∴</em>
<em />![\sqrt[3]{-1000x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1000x%5E4%7D)
<em />
<em>Simplifies to:</em>
<em />
<em />
<em />
<em> </em>
<em />
<em />
<em>Have a great day/night!</em>
69.75
I hope this helped you out!!
Answer:
(x-1)(x-1) and (x-3)(x+2)
Step-by-step explanation:
