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lozanna [386]
3 years ago
9

When the light turns yellow, should you stop or go through it? The article "Evaluation of Driver Behavior in Type II Dilemma Zon

es at High-Speed Signalized Intersections" (D. Hurwitz, M. Knodler, and B. Nyquist, Journal of Transportation Engineering, 2011:277-286) defines the "indecision zone" as the period when a vehicle is between 2.5 and 5.5 seconds away from an intersection. At the intersection of Route 7 and North Shrewsbury in Clarendon, Vermont, 154 vehicles were observed to encounter a yellow light in the indecision zone, and 21 of them ran the red light. At the intersection of Route 62 and Paine Turnpike in Berlin, Vermont, 183 vehicles entered the intersection in the indecision zone, and 20 ran the red light. Can you conclude that the proportion of redlight runners differs between the two intersections?
Mathematics
1 answer:
Natasha2012 [34]3 years ago
8 0

Answer:

No, does not differ.

Step-by-step explanation:

Given that there are two intersections route 7 and route 62.

At the intersection of Route 7 and North Shrewsbury in Clarendon, Vermont, 154 vehicles were observed to encounter a yellow light in the indecision zone, and 21 of them ran the red light. At the intersection of Route 62 and Paine Turnpike in Berlin, Vermont, 183 vehicles entered the intersection in the indecision zone, and 20 ran the red light.

Let p1 be the first proportion and p2 the second

We want to test whether these two proportions differ

H_0: p_1 = p_2\\H_a: p_1 \neq p_2

(two tailed test at 5% significance level)

test statistic = \frac{p_1-p_2}{\bar p (1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}

p_1 = 0.1363\\p_2 = 0.1093

Z statistic = 0.7554

p value = 0.4473

Since p >0.05 accept null hypothesis.

There is no significant difference and the proportion of redlight runners does not differ between the two intersections

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In kick boxing, the force needed to break a board varies inversely with the length of the board.If it takes 5 pounds of pressure
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

By taking k as constant:

P = k/L (where P is pressure, and L is length)

5 = k/2

k = 10

Therefore:

P = 10 / L

P = 10/ 8

P = 1.25 Pounds.

6 0
3 years ago
Stan guessed on all 10 questions of a multiple-choice quiz. Each question has 4 answer choices. What is the probability that he
algol13

ANSWER
0.756

EXPLANATION

Let x represent number of correct answers.

We can find

   P(x = 0 \text{ or } x = 1)

which leads us to

   P(x\ge 2) = 1 - P(x = 0\text{ or }x = 1)

which uses the compliment of P(x = 0\text{ or }x = 1) to find the probability of getting at least 2 questions correct.

Note that since P(x=0) and P(x=1) are mutually exclusive, we have

   P(x = 0\text{ or }x = 1) = P(x=0) + P(x=1)

Then P(x=0) = 3^{10}/4^{10} = (3/4)^{10} as we have 3^{10} to answer the questions incorrectly divided by the total 4^{10} to answer the questions.

Exactly 1 answer correct: P(x=1) = {}_{10}C_1 \cdot(3/4)^9(1/4)^1

Therefore

   \begin{aligned}
P(x \ge 2) &= 1 - P(x = 0\text{ or }x =1) \\
&=1 - \big[P(x=0) + P(x=1)\big] \\
&=1 - \left[ (3/4)^{10} + {}_{10}C_1 \cdot (3/4)^9(1/4)^1 \right] \\
&\approx 0.756
\end{aligned}

4 0
3 years ago
Read 2 more answers
The 1,840 rock concert tickets sold were twice the amount of jazz concert tickets sold
Yuki888 [10]
So there where two times the amount of rock tickets sold than the jazz concert. If that is it then you divide the 1840 by 2 getting 920, dividing 1÷2 you get zero remainder 1, 18÷2= 9, 4÷2= 2, and 0÷2= 0. 920. Hope i helped :)
8 0
3 years ago
Read 2 more answers
Use the Distributive Property to simplify this expression.<br> 15. (7 + 6w)6
antiseptic1488 [7]

(7+6w)6

 7 x 6 = 42

 6 x 6 = 36

so it becomes:

42 +36w

7 0
4 years ago
45/4140 show the work
kicyunya [14]

1/92

what is the number we can divide both 45 and 4140 by. it is 45. divide.

45/45=1

4140/45=92

the answer is 1/92

6 0
4 years ago
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