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Blizzard [7]
3 years ago
13

Use the Distributive Property to simplify this expression. 15. (7 + 6w)6

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

(7+6w)6

 7 x 6 = 42

 6 x 6 = 36

so it becomes:

42 +36w

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Choose the word that makes the sentence true. The first digit in the quotient 1,875 ÷9
motikmotik

Hi, I'm Jenny from ExperimentsDIYS and I'm here to help you with your math! :)

I am assuming that you need help with question #1 so we will proceed with that one.

Lets first divide 1,875 ÷ 9.

Using a calculator, this is equal to 208.333333333

We can simplify this number by rounding up.

208.33 would be your answer rounded.

The first digit in this quotient ( Which is the answer to a division problem) is using place value.

The decimal place value chart is attached.

The first digit will be in the hundreds place because it is on the left side of the decimal point.

We are ecstatic to help and if there are any more problems or if we got any answers wrong please tell us! Thank you <3

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Use the theorem in Sec. 28 to show that if f (z) is analytic and not constant throughout a domain D, then it cannot be constant
alexandr1967 [171]

Answer:

The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.

Step-by-step explanation:

Given

For any given function f(z), it is analytic and not constant throughout a domain D

To Prove

The function f(z) is non-constant constant in the neighbourhood lying in D.

Proof

1-Assume that the value of f(z)  is analytic and has a constant throughout some neighbourhood in D which is ω₀

2-Now consider another function F₁(z) where

F₁(z)=f(z)-ω₀

3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.

4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.

5-Replacing value of F₁(z) in the above gives:

F₁(z)≡0 in domain D

f(z)-ω₀≡0 in domain D

f(z)≡0+ω₀ in domain D

f(z)≡ω₀ in domain D

So this indicates that the value of f(z) for all values in domain D is a constant  ω₀.

This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.

6 0
3 years ago
A food company distributes its tomato soup in two cans of different sizes. For the larger can, both the diameter and the height
Lady_Fox [76]

Problem

A food company distributes its tomato soup in two cans of different sizes. For the larger can, both the diameter and the height have been increased by 15%.

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Every multiples of 10s has a zero... you do know that... right?
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