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3 years ago

What is 6 ones 7 hundredths -2.3

Mathematics

2 answers:

zmey [24]3 years ago

4 0

6 ones 7 hundredths -2.3

We make a place chart for 6 ones 7 hundredths. We write 0 in the remaining place value.

Hundred tens Ones point tenths hundredths thousandths

0 0 6 . 0 7 0

6 one 7 hundredths is 6.07

Now subtract 2.3 from 6.07

6.07 - 2.3 = 3.77

Answer : 3.77

julsineya [31]3 years ago

3 0

The answer to 6 ones 7 hundredths -2.3 equals to 3.77

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In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 3.0 m/s up a 22.0° inclined track

Aloiza [94]

Answer:

Approximately $0.31\; \rm m$ , assuming that $g = 9.81\; \rm N \cdot kg^{-1}$ .

Step-by-step explanation:

Initial kinetic energy of the sled and its passenger:

$\begin{aligned}\text{KE} &= \frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2} \times 14\; \rm kg \times (3.0\; \rm m\cdot s^{-1})^{2} \\ &= 63\; \rm J\end{aligned}$ .

Weight of the slide:

$\begin{aligned}W &= m \cdot g \\ &= 14\; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \\ &\approx 137\; \rm N\end{aligned}$ .

Normal force between the sled and the slope:

$\begin{aligned}F_{\rm N} &= W\cdot \cos(22^{\circ}) \\ &\approx 137\; \rm N \times \cos(22^{\circ}) \\ &\approx 127\; \rm N\end{aligned}$ .

Calculate the kinetic friction between the sled and the slope:

$\begin{aligned} f &= \mu_{k} \cdot F_{\rm N} \\ &\approx 0.20\times 127\; \rm N \\ &\approx 25.5\; \rm N\end{aligned}$ .

Assume that the sled and its passenger has reached a height of $h$ meters relative to the base of the slope.

Gain in gravitational potential energy:

$\begin{aligned}\text{GPE} &= m \cdot g \cdot (h\; {\rm m}) \\ &\approx 14\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times h\; {\rm m} \\ & \approx (137\, h)\; {\rm J} \end{aligned}$ .

Distance travelled along the slope:

$\begin{aligned}x &= \frac{h}{\sin(22^{\circ})} \\ &\approx \frac{h\; \rm m}{0.375}\end{aligned}$ .

The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:

$\begin{aligned} & - (-x)\, f \\ = \; & x \cdot f \\ \approx \; & \frac{h\; {\rm m}}{0.375}\times 25.5\; {\rm N} \\ \approx\; & (68.1\, h)\; {\rm J}\end{aligned}$ .

In other words, the sled and its passenger would have lost (approximately) $((137 + 68.1)\, h)\; {\rm J}$ of energy when it is at a height of $h\; {\rm m}$ .

The initial amount of energy that the sled and its passenger possessed was $\text{KE} = 63\; {\rm J}$ . All that much energy would have been converted when the sled is at its maximum height. Therefore, when $h\; {\rm m}$ is the maximum height of the sled, the following equation would hold.

$((137 + 68.1)\, h)\; {\rm J} = 63\; {\rm J}$ .

Solve for $h$ :

$(137 + 68.1)\, h = 63$ .

$\begin{aligned} h &= \frac{63}{137 + 68.1} \approx 0.31\; \rm m\end{aligned}$ .

Therefore, the maximum height that this sled would reach would be approximately $0.31\; \rm m$ .

7 0

2 years ago

-6 + -8 10 points plz help

satela [25.4K]

Answer

The answer is negative 14.

Step-by-step explanation:

When you add a negative by a negative it equals a negative. Like if you add 1 + 1 it's going to equal 2 which is a positive, not a negative. So the answer is technically 8 + 6 which is 14 and all you have to do is add a negative sign.

4 0

2 years ago

Which expression is equivalent to negative 32 5/3?

Sloan [31]

Im confused. Its not equal to any of the choices

Unless C is the cube root of 32^5.

[t3] \sqrt[n]{x} [32^5]

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2 years ago

The area of the parallelogram shown is (35x2 + 46x +15) square meters. If its base is (5x + 3) meters, find

attashe74 [19]

Answer:

(7x + 5)m

Step-by-step explanation:

area = base * height = (35x2 + 46x +15) m²

base = (5x + 3)

Using algebraic division, find the height. SEE ATTACHMENT

height = (7x + 5)

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2 years ago

How to solve 37=-3+5(x+6)

zavuch27 [327]

Distribute Property 5(x+6) basically means 5×x + 5×6 = 5x+30

37= -3+5x+30 (subtract 30 on both sides)

7=-3+5x (add three on both sides)

10= 5x (divide 5 on both sides)

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2 years ago