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Bad White [126]
3 years ago
13

What is the sum of 4.2 × 105 and 5.3 × 105?

Mathematics
2 answers:
Maru [420]3 years ago
8 0
4.2 times 105 is 441 and 5.3 times 105 is 556.5.
441 plus 556.5 is 997.5
So the answer is 997.5
Anvisha [2.4K]3 years ago
6 0
Hey there!

So, first we would do a first part if this problem.

4.2*105 

This would equal . . . .

\boxed{\boxed{441}}
_____________________________________________________________

Then we would do the second part of the problem.

5.3*105

This would equal . . . .

\boxed{\boxed{556.5}}

(By adding both (441) and also (556.5)

This would equal . . . 
                                                   
 \boxed{\boxed{\boxed{997.5}}}

Hope this helps.
~Jurgen                                   
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Arrange the steps in the correct order to perform this subtraction problem 1.1 ( 10 3 ) − 4.9 ( 10 2 ) = 610
Norma-Jean [14]

We are given :  Expression 1.1 ( 10^3 ) − 4.9 ( 10^2 ) = 610.

Solution: In order to solve above given expression, we need to apply order of operations.

We can apply order of operations according to PEMDAS rule.

PEMDAS stands for Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.

In the given problem, we need to simplify Parentheses first.

We have 10^3 and 10^2 in Parentheses.

10^3 = 10*10*10 = 1000.

10^2 = 10*10 = 100.

Substituting those values in original expression.

1.1 ( 1000 ) − 4.9 ( 100 ).

Now, we need to apply multiplication operation in 1.1*1000 and 4.9*100.

We get 1.1*1000 = 1100 and 4.9*100 = 490.

Substituting those values in above result we got.

1100-490.

Now, we can perform subtraction operation.

On subtracting 1100-490, we get 610.

And that is equal to 610.



7 0
3 years ago
10x + 8 = 3(x - 2)<br> 10x + 8 = 3x
lisabon 2012 [21]

Answer:

1) -2

2) 8/7

Step-by-step explanation:

1) 10x+8=3(x-2)

  10x+8=3x-6

  10x-3x=-6-8

  7x=-14

  x=-2

2) 10x+8=3x

   10x-3x=8

   7x=8

   x=8/7

Hope it helps

5 0
3 years ago
Find the distance between the points E(3, 7) and F(6, 5). The exact distance between the two points is .
S_A_V [24]

Answer:

\sqrt{13}

Step-by-step explanation:

The trick here is to know the distance formula (a formula that helps you find the distance between two points).

Distance formula: distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

But now that we know this, we can simply plug in our values and solve!

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\sqrt{(6-3)^2+(5-7)^2}\\\sqrt{(3)^2+(-2)^2}\\\sqrt{9+4}\\\sqrt{13}

Now we can tell from our answer that the distance between both points is \sqrt{13}

7 0
3 years ago
A scale drawing of a square has a side length of 6 millimeters. The drawing has a scale of 1 mm : 7 km. Find the actual perimete
zvonat [6]

Answer:

The real perimeter is:

P= 24 mm *\frac{7 km}{1mm}= 168 km

And the area would be:

P = 36mm^2 *\frac{(7km)^2}{(1mm)^2} = 1764 km^2

Step-by-step explanation:

For this case we know one side of a square given 6mm.

We can begin calculating the perimeter for the scale figure with this formula:

P = 4x = 4*6 mm =24 mm

The area for this case is given by:

A = x^2 = 6mm^2 = 36 mm^2

And we know that the drawing has a scale of 1 mm : 7 km and if we convert the perimeter to km we got:

P= 24 mm *\frac{7 km}{1mm}= 168 km

And the area would be:

P = 36mm^2 *\frac{(7km)^2}{(1mm)^2} = 1764 km^2

6 0
2 years ago
Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1
Alenkasestr [34]

Answer:

x=\frac{4*(2+e)}{e-2}

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

log(\frac{1}{x} )=-log(x)

log(x*y)=log(x)+log(y)

Therefore:

log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1

Now, cancel logarithms by taking exp of both sides:

e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e

Multiply both sides by (x-4)^{2} and using distributive propierty:

2x^{2} -32=16e-8ex+ex^{2}

Substract 16e-8ex+ex^{2} from both sides and factoring:

-(x-4)*(-8-4e-2x+ex)=0

Multiply both sides by -1:

(x-4)*(-8-4e-2x+ex)=0

Split into two equations:

x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0

Solving for x-4=0

Add 4 to both sides:

x=4

Solving for -8-4e-2x+ex=0

Collect in terms of x and add 4e+8 to both sides:

x(e-2)=4e+8

Divide both sides by e-2:

x=\frac{4*(2+e)}{e-2}

The solutions are:

x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}

If we evaluate x=4 in the original equation:

log(0)-log(0)=1

This is an absurd because log (x) is undefined for x\leq 0

If we evaluate x=\frac{4*(2+e)}{e-2} in the original equation:

log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1

Which is correct, therefore the solution is:

x=\frac{4*(2+e)}{e-2}

6 0
3 years ago
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