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vredina [299]
4 years ago
11

The Retread Tire Company recaps tires. The fixed annual cost of the recapping operation is $65,000. The variable cost of recappi

ng a tire is $7.5. The company charges$25 to recap a tire.
a. For an annual volume of 15, 000 tire, determine the total cost, total revenue, and profit. b. Determine the annual break-even volume for the Retread Tire Company operation.
Mathematics
1 answer:
trasher [3.6K]4 years ago
3 0

Part a) Total Cost

Total Cost for recapping the tires is the sum of fixed cost and the variable cost. i.e.

The total cost is ( $65,000 fixed) + (15,000 x $7.5)

=$65,000+$112,500

=$177,500  

Part b) Total Revenue

Revenue from 1 tire = $25

Total tires recapped = 15000

So, Total revenue = 15000 tires x $25/tire

Total Revenue =$375,000  

Part c) Total Profit

Total Profit = Revenue - Cost

Using the above values, we get:

Profit = $375,000 - $177,500

Profit = $197,500  

Part d) Break-even Point

Break-even point point occurs where the cost and the revenue of the company are equal. Let the break-even point occurs at x-tires. We can write:

For break-even point

Cost of recapping x tires = Revenue from x tires

65,000 + 7.5 x = 25x

65,000 = 17.5 x

x = 3714 tires

Thus, on recapping 3714 tires, the cost will be equal to the revenue generating 0 profit. This is the break-even point.

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The answer to the question

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3 years ago
What is 57.42 + 4 + 1.02? Pls help and I need a small simple explanation...
vova2212 [387]

Answer:

62.44

Step-by-step explanation:

Line up the decimals and then add them up like usual, and then place the decimal where it should go. THen you get your answer.

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6 0
4 years ago
Read 2 more answers
Of 560 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared
frutty [35]

Answer:

a) (0.5256,0.5944)  

c) Criticism is invalid

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 560

Proportion of mislabeled = 56%

\hat{p} = 0.56

a) 90% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64

Putting the values, we get:

0.56\pm 1.64(\sqrt{\dfrac{0.56(1-0.56)}{560}}) = 0.56\pm 0.0344\\\\=(0.5256,0.5944)

b) Interpretation of confidence interval:

We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.

c) Validity of criticism

Conditions for validity:

np > 10\\n(1-p)>10

Verification:

560\times 0.56 = 313.6>10\\560(1-0.56) = 246.4>10

Both the conditions are satisfied. This, the criticism is invalid.

8 0
4 years ago
A Boy obtained 80 percent marks.If the full marks is 800,how much did he get?​
ollegr [7]

9514 1404 393

Answer:

  640 marks

Step-by-step explanation:

80% of 800 is ...

  0.80 × 800 = 640

He got 640 marks.

5 0
3 years ago
The monthly revenue of a certain company is given by R 820p-7p, where p is the price in dollars of the product the company manuf
lora16 [44]

The revenue will be 12,000 when the price of the product  is $100

Given :

The monthly revenue of a certain company

R=820p-7p^2

We need to find out p when <u>Revenue R is 12000</u>

Lets replace R with 12000 and solve for p

12000=820p-7p^2\\820p-7p^2=12000\\-7p^2+820p-12000=0

Apply <em>quadratic formula </em>

p=\frac{-820\pm \sqrt{820^2-4\left(-7\right)\left(-12000\right)}}{2\left(-7\right)}\\p=\frac{-820\pm \:580}{2\left(-7\right)}\\p=\frac{-820+580}{2\left(-7\right)},\:p=\frac{-820-580}{2\left(-7\right)}\\p=\frac{120}{7},\:p=100

Given that price must be greater than 50

So the revenue will be 12000 when the price of the product  is $100

Learn more :  brainly.com/question/21503855

5 0
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