Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
Step-by-step explanation: I think not sure.
Answer:
A. yes
Step-by-step explanation:
The contestant has a 60% chance of winning because they could either spin 1, 3, or 5.
However, unless there's another player who can only spin evens, it's not fair, because the contestant who spins odds has a 60% chance, while this player will only have a 40% chance.
46.06 would be the answer
Step-by-step explanation:
It's an irrational number.
![\sqrt[3]{275:7}=\sqrt[3]{\dfrac{275}{7}}=\dfrac{\sqrt[3]{275}}{\sqrt[3]{7}}=\dfrac{\sqrt[3]{275}\cdot\sqrt[3]{7^2}}{\sqrt[3]{7}\cdot\sqrt[3]{7^2}}=\dfrac{\sqrt[3]{275\cdot49}}{\sqrt[3]{7\cdot7^2}}\\\\=\dfrac{\sqrt[3]{13475}}{\sqrt[3]{7^3}}=\dfrac{\sqrt[3]{13475}}{7}=\dfrac{1}{7}\sqrt[3]{13475}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B275%3A7%7D%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B275%7D%7B7%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%7D%7D%7B%5Csqrt%5B3%5D%7B7%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%7D%5Ccdot%5Csqrt%5B3%5D%7B7%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B7%7D%5Ccdot%5Csqrt%5B3%5D%7B7%5E2%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%5Ccdot49%7D%7D%7B%5Csqrt%5B3%5D%7B7%5Ccdot7%5E2%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B13475%7D%7D%7B%5Csqrt%5B3%5D%7B7%5E3%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B13475%7D%7D%7B7%7D%3D%5Cdfrac%7B1%7D%7B7%7D%5Csqrt%5B3%5D%7B13475%7D)
