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galben [10]
3 years ago
5

What are the steps to solve this?

Mathematics
1 answer:
Tema [17]3 years ago
3 0
\lim_{x\to3^-}\frac{x+5}{x-3}=\\
\lim_{x\to3^-}\frac{3+5}{0^-}=\\
\lim_{x\to3^-}\frac{8}{0^-}=\\
-\infty
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How do you solve using the Elimination Method?<br> 2x-4y=12<br> -x+2y=-6
Paladinen [302]

Answer:

Step-by-step explanation:

2x-4y=12.........(1)

-x+2y=-6..........(2)

Multiply equation (2) by 2

-2x + 4y = -12........(3)

Adding (3) from (1)

2x + (-2x) - 4y + 4y = 12 + (-12)

2x - 2x - 4y + 4y = 12 - 12

Ox -0y = 0

No solution

4 0
3 years ago
What is the solution to the system of equations
vitfil [10]

Answer:

Step-by-step explanation:

Hello

I believe there is an error in the question

we have two equations and need to find x and y

(1) \dfrac{1}{4}x+\dfrac{1}{2}y=\dfrac{5}{8}\\(2) \dfrac{3}{4}x-\dfrac{1}{2}y=3\dfrac{3}{8}

let s multiply by 8 so that we can get rid of the fractions

(1) becomes 2x+4y=5

(2) becomse 6x-4y=9

if we sum it gives

2x+4y+6x-4y=9+5

8x=14

x = 14/8 = 7/4

and then from the first equation

4y = 5 - 7/4

<=> 16y = 20-7 = 13

y = 13/16

the solutions is (7/4,13/16)

5 0
3 years ago
A college parking lot is 140 ft long and 90 ft wide. The college wants to increase the area of the lot by 29% by adding strips o
Novay_Z [31]
The initial dimenssions of the park lot are:

length: 140 ft
width: 90 ft

initial area: 140 * 90 = 12,600 ft^2

Area increased 29% = 12,600 * 1.29 = 16,254 ft^2

width of the strips: x

New length: 140 + x

New width: 90 + x

New area: (140+x)(90+x) = 16,254

Solution of the equation:

12600 + 230x + x^2 = 16254

=> x^2 + 230x - 3654 = 0

Use the quadratic formula.

x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =

x = 14.92

The other solution is negative so it is discarded.

Answer: 15 ft


 
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4 years ago
Divide 3,479 by 9. What is the remainder?
maxonik [38]
5/9 is the remainder
4 0
3 years ago
What does 807 divided by 7
Contact [7]
807 divided by 7 = 115.2857143
6 0
3 years ago
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