3 years ago

What are the steps to solve this?

Mathematics

1 answer:

Tema [17]3 years ago

3 0

$\lim_{x\to3^-}\frac{x+5}{x-3}=\\
\lim_{x\to3^-}\frac{3+5}{0^-}=\\
\lim_{x\to3^-}\frac{8}{0^-}=\\
-\infty$

You might be interested in

1/3x +5<br><br> x=-6<br><br> pls help!!!

lara [203]

Answer:

x = - 9/8

Explanation:

3 0

3 years ago

If the length of the radius of the circle is 6, what is the area of the square? 6 72 48 12 144

lawyer [7]

Answer:

If the circle is inside the square the area of the square is 144

Step-by-step explanation:

The diameter of a circle is equal to the side length of a square.

So $d = 2r$ the diameter of the circle is 2(6)=12

so one side length of the equals 12

Area of square = $s^{2}$ $12^{2} = 144$

7 0

3 years ago

What is the value of x In the equation 2(2x – 5 – 4) = 160 - 17? (4 points)

rosijanka [135]

Answer:

Step-by-step explanation:

Exact Form:

x =161

Decimal Form:

x = 40.25

Mixed Number Form:

x = 40 1

6 0

3 years ago

Read 2 more answers

In parallelogram ABCD,AB^4+AD^2+AB^2*AD^2=AC^2*BD^2.If angle ABC=x,find the product of all possible values of x

almond37 [142]

Answer:

Hello,

Step-by-step explanation:

AB=DC=b, AD=BC=a

p=BD, q=AC

angle ABC=x

$AB^4+AD^4+AB^2*AD^2=AC^2*BD^2\\\\b^4+a^4+b^2a^2=(a^2+b^2+2abcos(X))(a^2+b^2-2abcos(X)\\\\(a^2+b^2+2a^2b^2)-a^2b^2=((a^2+b^2)^2-4a^2b^2*cos^2(X))\\\\\\4a^2b^2cos^2(X)=a^2b^2\\\\\\cos^2(X)=\dfrac{1}{4} \\\\(cos(X)-\dfrac{1}{2} )(cos(X)+\dfrac{1}{2} )=0\\cos(x)=\frac{1}{2} \ or\ cos(X)=\dfrac{-1}{2} \\\\\\X=60^o =\dfrac{\pi}{3} rad \ or \ X=120^o=\dfrac{4\pi}{3} rad\\\\\\\\Product=\dfrac{\pi}{3}*\dfrac{4\pi}{3} =\boxed{\dfrac{4\pi^2}{9}}\\$

8 0

3 years ago

Solve the equation h+16=31

ira [324]

Answer:

h=15

Step-by-step explanation:

subtract 16 from 31

4 0

3 years ago

Read 2 more answers