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Anna [14]
2 years ago
5

Please help me with these two algebra questions. Image attached.

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
7 0

1. when x⇒∞, y=∞ and when x⇒-∞, y=-∞

So, we have a odd degree polynomial (x³ or x^5 or even x^9).

The leading coefficient is negative its end behavior matches x³ which has a positive leading coefficient.

2. when x⇒∞, y=∞ and when x⇒-∞, y=∞

So, we have a even degree polynomial (x² or x^4 or even x^{100}).

And because it matches these parent functions listed above (they all have positive leading coefficients), the leading coefficient is again positive.

answers:

1. odd and positive

2. even and positive

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<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x + C.</em></u>

Step-by-step explanation:

<u><em>First step we aplicate distributive property to the function.</em></u>

<u><em>5*(x+a)*(x+b)= 5*[x^{2}+x*b+a*x+a*b]</em></u>

<u><em>5*[x^{2}+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>

<u><em>integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant</em></u>

<u><em>∫^5*[x^{2}+x*(a+b)+a*b]*dx, apply integral´s property</em></u>

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<u><em>5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x</em></u>

<u><em>Finally we can write the function F(x)</em></u>

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x ]+ C.</em></u>

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