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Serjik [45]
3 years ago
11

Meredith interviews all of the students of her school who took both AP tests and the SAT. She finds that the relationship betwee

n the number of AP tests and SAT scores is linearly associated with a correlation coefficient of 0.93. What does this value suggest about the relationship between the number of AP tests and SAT scores
Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0
Correlation coefficient is the numerical representation of how one variable predicts the change of the other. In this case, if the AP tests scores and the SAT scores have 0.93 correlation coefficient, this means that the two results move in the same direction. When AP test results go up, then we can say that SAT scores will go up too, same also if one goes down, so does the other.
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The table shows a golfers score for four rounds of a recent U.S. Women’s Open. Her total score was even with par. What was her s
dexar [7]
The answer for the third round is S = +2
7 0
4 years ago
Compare the fractions 5 by 9 and 6 by 11​
alukav5142 [94]

Answer:

5/9 and 6/11

= 5/9 × 11/11 and 6/11 × 9/9

= 55/99 and 54/99

= 55/99 > 54/99

<em>therefore, 5 by 9 is greater than 6 by 11</em>

4 0
3 years ago
Given the triangle shown below, find the length of [BC]​
marshall27 [118]

Hyp²=ADJ²+OPP²

28²=17²+X²

784=289+x²

x²=784-289

x²=495

x=22

here is your answer 22

6 0
3 years ago
What is (10y+6) (8y-6) ?
ANEK [815]

Answer:

y = 3/4 or y = -3/5

Step-by-step explanation:

Solve for y:

(8 y - 6) (10 y + 6) = 0

Hint: | Find the roots of each term in the product separately.

Split into two equations:

8 y - 6 = 0 or 10 y + 6 = 0

Hint: | Look at the first equation: Factor the left hand side.

Factor constant terms from the left hand side:

2 (4 y - 3) = 0 or 10 y + 6 = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 2:

4 y - 3 = 0 or 10 y + 6 = 0

Hint: | Isolate terms with y to the left hand side.

Add 3 to both sides:

4 y = 3 or 10 y + 6 = 0

Hint: | Solve for y.

Divide both sides by 4:

y = 3/4 or 10 y + 6 = 0

Hint: | Look at the second equation: Factor the left hand side.

Factor constant terms from the left hand side:

y = 3/4 or 2 (5 y + 3) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 2:

y = 3/4 or 5 y + 3 = 0

Hint: | Isolate terms with y to the left hand side.

Subtract 3 from both sides:

y = 3/4 or 5 y = -3

Hint: | Solve for y.

Divide both sides by 5:

Answer: y = 3/4 or y = -3/5

4 0
4 years ago
There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit
DaniilM [7]

Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = nCr * p^{r} * q^{n-r}

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = 15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}

p(x=3) = 455 * 0.4^{3} * 0.6^{12}

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday  = 1 - 0.0633 = 0.9337

3 0
3 years ago
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