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3 years ago

I need help with 7-10 please!

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

6 0

7:
3/8 = 6/x
3x = 48
x = 16

8:
4/5 = (x+7)/40
160 = 5x + 35
5x = 125
x = 25

9:
3/8 = 12/(x-3)
3x - 9 = 96
3x = 105
x = 35

10:
4/1 = (3x+6)/x
4x = 3x + 6
x = 6

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The rectangle below has an area of 70y^8+30y^6.The width of the rectangle is equal to the greatest common monomial factor of 70y

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Width $10y^6$ units

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4 years ago

Which choice is equivalent to the expression below when y2 0? √y^2 + √16y^3 – 4y√y

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Option C.

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We start with the expression:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

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We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

$\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}$

And:

$y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}$

If we apply these two to our initial expression, we can rewrite it as:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

$\sqrt{y^3} + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}$

Here we can use the second simplification again, to rewrite:

$\sqrt{y^3} = y*\sqrt{y}$

So, concluding, we have:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}$

Then the correct option is C.

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