Answer:
The placement of fossils throughout the surface layers of Earth made the geologists decide where one division of the geologic time scale ends and the next begins.
Explanation:
Fossils play a major role in identifying or deciding the geologic time scale eras or eons. Fossils are the only evidence in the form of specimen remains like bones, leaves, shells, teeth, or burrows, tracks etc all of which provide information about life on Earth during a particular time.
Fossil placement on earth’s surface creates fossil records. On the earth’s surface like rocks, a younger fossil will be buried on a layer above the older fossil layer. Each layer will represent a unique life form that existed during a time period and determines the division of geologic time scale.
In fact each of the eras like Paleozoic, Mesozoic, or Cenozoic ends with the suffix zoic since the time change of these eras is based on the evolution of animal life during that period
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Answer:
My answer would also be as yours
Explanation:
at the bottom of the ocean
Answer:
a tube-like body attached to a firm surface with tentacles on the opposite side of the attachment, surrounding the animal's mouth
Explanation:
A polyp is a type of body structure that a cnidarian can assume. The cnidarians, in turn, are invetebrate animals of aquatic life. This group of animals includes jellyfish, corals and sea anemones.
In polyp form, cnidarians are not actively moving, although some do move when they feel threatened. This is because they appear as a tubular structure, with one end fixed to the sea floor. The other end presents the animal's mouth, which is surrounded by tentacles that are responsible for capturing the prey needed for food.
The smallest particle that an element can be divided into is the atom, which is the smallest unit of anything.
Answer:
B. 0.42
Explanation:
Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1
According to the given information, the frequency of one allele in the population is= 0.7
This means that the frequency of the other allele would be= 1-0.7 = 0.3
Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42
