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Sedaia [141]
4 years ago
15

The length of a rectangle is 5 mm less than 4 times the width. If the perimeter is 75 mm, what is the length of the rectangle?

Mathematics
1 answer:
Alborosie4 years ago
4 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{29 \: mm}}}}}

Step-by-step explanation:

Let the width of a rectangle be 'w'

Length of a rectangle be 4w - 5

Perimeter of a rectangle = 75 mm

<u>First,</u><u> </u><u>finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>rectangle</u><u> </u><u>(</u><u> </u><u>w</u><u> </u><u>)</u>

\boxed{ \sf{perimeter \: of \: a \: rectangle = 2(length + width)}}

\dashrightarrow{ \sf{75 = 2(4w - 5 + w)}}

\dashrightarrow{ \sf{75 = 2(5w - 5)}}

\dashrightarrow{ \sf{75 = 10w - 10}}

\dashrightarrow{ \sf{10w - 10 = 75}}

\dashrightarrow{ \sf{10w = 75 + 10}}

\dashrightarrow{ \sf{10w = 85}}

\dashrightarrow{ \sf{ \frac{10w}{10}  =  \frac{85}{10} }}

\dashrightarrow{ \sf{w = 8 .5 \: mm}}

<u>Replacing</u><u> </u><u>/</u><u> </u><u>substit</u><u>uting</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>in</u><u> </u><u>order</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>length </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle </u>

\sf{length \: of \: a \: rectangle = 4w - 5}

\dashrightarrow{ \sf{4 \times 8.5 - 5}}

\dashrightarrow{ \sf{34 - 5}}

\dashrightarrow{ \sf{29 \: mm}}

Length of a rectangle = 29 mm

Hope I helped!

Best regards! :D

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