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3 years ago

11

How do you simplify 19/228

2 answers:

rodikova [14]3 years ago

8 0

Answer:

The simplest form of 19/228 is 1/12

Step-by-step explanation:

19/228

We reduce with 19 as 19 and 228 are both factors of 19

We will have something like

(19÷19)/(228÷19)

1/12

Brilliant_brown [7]3 years ago

3 0

you find what they both divide by and then divide each one and then you keep doing that until you cant no more

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(-2/3)^7*(3/5)^6*(5/6)^5*(1/3)^-7 simplify of law of indices

Wewaii [24]

Answer:

$\boxed {-\frac{12}{5}}$

Step-by-step explanation:

Solve the following expression:

$(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $-\frac{2}{3}$ to the power of $7$ :

$(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{3}{5}$ to the power of $6$ :

$-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Multiply both $-\frac{128}{2187}$ and $\frac{729}{15625}$ :

$-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{5}{6}$ to the power of $5$ :

$-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}$

-Multiply both $-\frac{128}{46875}$ and $\frac{3125}{7776}$ :

$-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}$

$-\frac{4}{3645} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{1}{3}$ to the power of $-7$ :

$-\frac{4}{3645} \times (\frac{1}{3})^{-7}$

$-\frac{4}{3645} \times 2181$

-Multiply both the $-\frac{4}{3645}$ and $2187$ :

$-\frac{4}{3645} \times 2181$

$\boxed {-\frac{12}{5}}$

Therefore, the final answer is $-\frac{12}{5}$ .

3 0

3 years ago

To get to his office from home, Greg walks 6 blocks north and then 3 blocks east. After work he meets some friends at a cafe; to

Nataly [62]

Answer:

total distance = 3300 ft

Step-by-step explanation:

we know here displacement S is in vector form that is

$\vec{S} = \vec{S1} +\vec{S2}+\vec{S3}+\vec{S4}$ ......................1

$\vec{S} = (3\hat{i}+6\hat{j}) + (-7\hat{i}-3\hat{j})$

and

$\vec{S} =(-4\hat{i}+3\hat{j})$

and

magnitude is

$\left| \vec{S} \right| = \sqrt{(-4)^2+3^2}$

$\left| \vec{S} \right| = \sqrt{25}$

$\left| \vec{S} \right| = 5$

so here distance from home to cafe is

S = 5 × 660

total distance = 3300 ft

7 0

3 years ago

When placed near a second charge, a 60-μC charge experiences a force of 0.30 N. What is the electric field strength at the locat

jeka57 [31]

Answer:

$E=5000N/C$

Step-by-step explanation:

From the question we are told that

Charge $q= 60 \mu C$

Force $F_=0.30N$

Generally the equation for electric field strength is mathematically given as

$E=F/q$

$E=\frac{0.30}{60*10^-^6}$

Therefore

$E=5000N/C$

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2 years ago

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alexgriva [62]

Answer:

3,500=3.5

500=0.5

75=0.075

1=0.001

x=x÷1000

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Answer:

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Step-by-step explanation:

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