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2 years ago

Answer ASAP and both questions :D

Mathematics

2 answers:

Nesterboy [21]2 years ago

5 0

(a.) Her reasoning is incorrect because the closest perfect square is not 200, it is 49.

(b)

We can estimate the square root of 200 with 196 because it is the closest perfect square. square root of 296 is 14.

dangina [55]2 years ago

4 0

the student needed to place a ten outside the radical, as a perfect square of 100 composes 200. This way, a two should be left under the radical sign. Also, this would be about 14.1 because 14^2 is 196 and 15^2 is 225. The correct answer must be less than 225, more than 196, but closer to 196. Therefore, a .1 is added to the 14

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Write the ratio for each:<br><br> Sin=?/? <br> Cos=?/?<br> tan=?/?

Sav [38]

Sin=opposite side/hypotenuse
cos=adjacent side/hypotenuse
tan=sin/cos or opposite/adjacent

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2 years ago

The length of a rectangle is eight more than twice its width. The perimeter is 96 feet. Find the dimensions of the rectangle

Debora [2.8K]

Answer:

The width of the rectangle is 14'8", and the length is 33'4"

Step-by-step explanation:

We're given two pieces of information:

The length is eight more than twice the width:

$l = 2w + 4$

The perimeter is 96 feet:

$p = 96$

We also need to apply one more piece of information that is not provided here, and that is the relationship between the perimeter of a rectangle, and it's length and width:

$p = 2l + 2w$

We can solve for w by plugging the other two values into the last:

$p = 2w + 2l\\96 = 2w + 2(2w + 4)\\96 = 2w + 4w + 8\\88 = 6w\\3w = 44\\w = \frac{44}{3}\\w = 14\frac{2}{3}$

Now we can find the length by plugging w into the first equation:

$l = 2w + 4\\l = 2(14\frac{2}{3}) + 4\\l = 29\frac{1}{3} + 4\\l = 33\frac{1}{3}$

One third of a foot is four inches, so the width is 14'8" and the length is 33'4"

To make sure our answer is correct, we should plug those numbers back into the area equation and see if we're right:

$p = 2l + 2w\\p = 2(33\frac{1}{3}) + 2(14\frac{2}{3})\\p = 66\frac{2}{3} + 29\frac{1}{3}\\p = 96$

So we know our answer's correct

8 0

2 years ago

At Brighton Middle School, Mr. Yule asked 50 randomly selected students from each grade level about their favorite subject, and

Ugo [173]

Answer:

Yes, he made a reasonable inference by saying about 25 percent of students choose the science.

Step-by-step explanation:

Given that

Number of students for survey = 50

Number of students who choose science = 12

Now

Percentage of student who choose science = $\frac{12}{50} x 100$

Percentage of student who choose science = $\frac{12*100}{50}$

Percentage of student who choose science = 24 %

Now as Mr. Yule said "about 25" percent of students choose the science it can be treated as reasonable approximation.

Now if the number of students in survey become 200, then we can expect 12 out of every 50 students would choose the science. So, in total 48 students would choose the science.

Now lets calculate the percentage of students who choose science.

Percentage of student who choose science = $\frac{48}{200} x 100$