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4 years ago

I need help with this question?????

Mathematics

2 answers:

sergiy2304 [10]4 years ago

7 0

Diameter = circumference / pi = 28.26 / pi = 9.00 units (to the nearest hundredth)

Novay_Z [31]4 years ago

4 0

Since circumference= $\pi$ d,

You would solve for d, using the equation 28.26= $\pi$ d, since 28.26 is the circumference.

You would end up dividing $\pi$ on both sides, thus getting the exact answer of 28.26/ $\pi$ as the diameter. If you need an estimated answer, then use a calculator, enter the exact diameter, and round as needed.

(If there's anything wrong/unclear in my explanation then please tell me as this is my first time doing this)

Have a great day!

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Step-by-step explanation:

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4 years ago

Question 3 (1 point) Co-60 has a half life of 5.3 years. If a pellet that has been in storage for 26.5 years contains 14.5g of C

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Answer:

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Step-by-step explanation:

Amount of substance:

The amount of substance after t years is given by an equation in the following format:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Co-60 has a half life of 5.3 years.

This means that:

$A(5.3) = 0.5A(0)$

We use this to find r. So

$A(t) = A(0)(1-r)^t$

$0.5A(0) = A(0)(1-r)^{5.3}$

$(1-r)^{5.3} = 0.5$

$\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}$

$1 - r = 0.5^{\frac{1}{5.3}}$

$1 - r = 0.8774$

$A(t) = A(0)(0.8774)^{t}$

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?

We have that $A(26.5) = 14.5$ , and use this to find A(0). So

$A(t) = A(0)(0.8774)^{t}$

$14.5 = A(0)(0.8774)^{26.5}$

$A(0) = \frac{14.5}{(0.8774)^{26.5}}$

[tex]A(0) = 464[tex]

464 grams.

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