Answer:
Nevan won the game.
He scored 183 points.
Explanation:
Correct answer is worth 13/4 points
Incorrect answer is worth -1/4 points.
Number of correct answers = 58
Number of incorrect answers = 22
Point scored 
Points need to win = 90 points
Point scored, 183 >Points need to win, 90
So, Nevan won the game.
Answer: The answer would be B
Step-by-step explanation:
I had a test like this so I kinda know wut the answer is a few weeks or so ago but u need to multiply -5 • 5 (which would be negative since it has one negative sign) then multiply -5 • -5 (since it has another negative it’s positive) then u just multiply the answers that u got from the times 5 u did -bonus if it’s 1 negatives it’s a negative but if it’s 2 negatives it’s a positive
Answer:
Step-by-step explanation:
x ≓ -2.009940617
Answer:

Step-by-step explanation:
Given two non zero vectors,
.
Let the angle between the two vectors = 
Given that:

Let us have a look at the formula for magnitude of addition of two vectors:

Where
is the angle between the two vectors.
formula for magnitude of subtraction of two vectors:

As per the given condition:

Squaring both sides:

So, the angle between the two vectors is: 
Answer:
To show that an equation is an identity: Start with either side of the equation and show that it can algebraically be changed into the other side. Or start with both sides of the equation and show that they both can be changed into the same algebraic expression.
Step-by-step explanation: