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Reptile [31]
3 years ago
8

Evaluate (4p)3 when p = (-1)

Mathematics
1 answer:
Leona [35]3 years ago
3 0

Answer:

-12

Step-by-step explanation:

plug in -1 into the equation which is going to be (4*-1)3

you multiply what is in the parenthesis first and after is going to be (-4)3

lastly your going to multiply -4*3 and it is going to equal to -12.

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Can anyone help me figure this out? It’s not 75 x 0.20.. thank you :) I’ll give Brainly!!
cluponka [151]

Answer:

60

Step-by-step explanation:

Dividends are paid quarterly and it wants the annual amount, so you have to mulitply what you originally got by 4

or

75*.2*4=60

8 0
3 years ago
Read 2 more answers
What is the slope of the line passing through the points (1, 2) and (5, 4)?​
bulgar [2K]
<h2>SOLVING</h2>

\Large\maltese\underline{\textsf{A. What is Asked}}

What is the slope of the line passing through the point (1,2) and (5,4)

\Large\maltese\underline{\textsf{This problem has been solved!}}

Formula used, here  \bf{\dfrac{y2-y1}{x2-x1}

_______________________________________________________

\bf{\dfrac{4-2}{5-1} | simplify

\bf{\dfrac{2}{4} | reduce

\bf{\dfrac{1}{2}

\rule{300}{1.7}

\bf{Result:}

         \bf{=Slope:\dfrac{1}{2}

\boxed{\bf{aesthetic\not101}}

3 0
2 years ago
Read 2 more answers
Each of the 9 parking lots at an automobile plant holds the same number of new cars. The lots lots are full. If there are 431 ca
Serjik [45]

431 \div 9
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3 years ago
Seamus plays outside for five and five sixths hours every week. He has already played outside for four and three sixths hours. H
Ira Lisetskai [31]
I think it’s C because I did have this question but I’m not sure
5 0
3 years ago
I will attach a screenshot of the math problem.
Alekssandra [29.7K]

Complete the table for the function y = 0.1^x

The first step: plug values from the left column into the ‘x’ spot in the formula <u>y=0.1^x</u>.

* 0.1^-2 : We can eliminate the negative exponent value by using the rule a^-1 = 1/a. Keep this rule in mind for future problems. (0.1^-2 = 1/0.1 * 0.1 = 100).

* 0.1^-1 = 1/0.1 = 10

* 0.1^0 = 1 : (Remember this rule: a^0 = 1)

* 0.1^1 = 0.1

Our list of values: 100, 10, 1, 0.1

Now, we can plug these values into your table:

\left[\begin{array}{ccc}x&y\\2&10\\1&10\\0&1\\1&0.1\end{array}\right]

The points can now be graphed. I will paste a Desmos screenshot; try to see if you can find some of the indicated (x,y) values: [screenshot is attached]

I hope this helped!

7 0
3 years ago
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