Question

Any one plz solve this i tried thousands time step by step​

Answer 1

Answer:

xy-x+y+1

Step-by-step explanation:

(1-x^2)(1-y^2)+4xy=1-y^2-x^2+x^2y^2+4xy

here, 4xy=2xy+2xy

then, -(x^2-2xy+y^2)+(x^2y^2+2xy+1)=-(x-y)^2+(xy+1)^2

by a^2-b^2=(a+b)(a-b)

(xy+1+x-y)(xy+1-x+y)

1-2x+y-x^2y+x^2=-y(x^2-1)+(x^2-2x+1)=-y(x+1)(x-1)+(x-1)^2

=(x-1)(x-1-xy-y)=-(x-1)(xy-x+y+1)

thus, common factor is xy-x+y+1

Hope this helps

Answer 2

Answer:

please tell me if there iscany sing after 4xy