Answer:
A=36
B=36
C=108
Step-by-step explanation:
A =B
2A+C=180
C is greater than A
2A+(A+72) =180
SIMPLIFY
3A +72=180
-72 ON BOTH SIDES
3A=108
DIVIDE BY 3
A=36
SO
B=36
36 TIMES 2 IS 72
180-72=108
SO
C=108
hope this helps
The second term of the given sequence aₙ = -5(n² + 1n) when solved gives us; a₂ = -20
<h3>How to find the nth term of a sequence?</h3>
We are given the formula for a sequence as;
aₙ = -5(n² + 1n)
Where n is the position of the term.
Now, for the first term, we will have;
a₁ = -5(1² + 1(1))
a₁ = -10
The second term of the sequence is;
a₂ = -5(2² + 1(2))
a₂ = -20
Read more about Sequence at; brainly.com/question/6561461
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Answer:
yes you can
Step-by-step explanation:
if you rounded 18.3 to the tenth it would be 183 and if you rounded it to the hundreds it would be 1,830
Step-by-step explanation:
vbfhhfhhhchhhhhhhhhhhhh
If the ball was thrown straight up at 24 ft/sec when it was 5 ft above the ground, the ball reached a maximum height of 7.25 m
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Further explanation</h3>
Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :
<h2>D = b² - 4 a c</h2>
From the value of Discriminant , we know how many solutions the equation has by condition :
D < 0 → No Real Roots
D = 0 → One Real Root
D > 0 → Two Real Roots
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
An axis of symmetry of quadratic equation y = ax² + bx + c is :
![\large {\boxed {x = \frac{-b}{2a} } }](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7Bx%20%3D%20%5Cfrac%7B-b%7D%7B2a%7D%20%7D%20%7D)
Let us now tackle the problem!
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<u>Given:</u>
![p(t) = 3gt^2 + v_ot + p_o](https://tex.z-dn.net/?f=p%28t%29%20%3D%203gt%5E2%20%2B%20v_ot%20%2B%20p_o)
![p(t) = 3(-32)t^2 + 24t + 5](https://tex.z-dn.net/?f=p%28t%29%20%3D%203%28-32%29t%5E2%20%2B%2024t%20%2B%205)
![p(t) = -64t^2 + 24t + 5](https://tex.z-dn.net/?f=p%28t%29%20%3D%20-64t%5E2%20%2B%2024t%20%2B%205)
<u>Asked:</u>
![p_{max} = ?](https://tex.z-dn.net/?f=p_%7Bmax%7D%20%3D%20%3F)
<u>Solution:</u>
<em>At the maximum height , velocity is 0 m/s:</em>
![v = \frac{dp(t)}{dt}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bdp%28t%29%7D%7Bdt%7D)
![v = \frac{d}{dt} ( -64t^2 + 24t + 5 )](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bdt%7D%20%28%20-64t%5E2%20%2B%2024t%20%2B%205%20%29)
![v = -128t + 24](https://tex.z-dn.net/?f=v%20%3D%20-128t%20%2B%2024)
![0 = -128t + 24](https://tex.z-dn.net/?f=0%20%3D%20-128t%20%2B%2024)
![128t = 24](https://tex.z-dn.net/?f=128t%20%3D%2024)
![t = 24 \div 128](https://tex.z-dn.net/?f=t%20%3D%2024%20%5Cdiv%20128)
![t = 3 \div 16](https://tex.z-dn.net/?f=t%20%3D%203%20%5Cdiv%2016)
![t = 0.1875 \texttt{ s}](https://tex.z-dn.net/?f=t%20%3D%200.1875%20%5Ctexttt%7B%20s%7D)
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
![p(t) = -64t^2 + 24t + 5](https://tex.z-dn.net/?f=p%28t%29%20%3D%20-64t%5E2%20%2B%2024t%20%2B%205)
![p(0.1875) = -64(0.1875)^2 + 24(0.1875) + 5](https://tex.z-dn.net/?f=p%280.1875%29%20%3D%20-64%280.1875%29%5E2%20%2B%2024%280.1875%29%20%2B%205)
![p(0.1875) = 7.25 \texttt{ m}](https://tex.z-dn.net/?f=p%280.1875%29%20%3D%207.25%20%5Ctexttt%7B%20m%7D)
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Learn more</h3>
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Answer details</h3>
Grade: High School
Subject: Mathematics
Chapter: Quadratic Equations
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
Keywords: Quadratic , Equation , Discriminant , Real , Number
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