Solve for x. 5x+3=23

at 9 a.m. the way of the paper in the recycling bin with 60 lb 1 hour later you wait in the recycling bin increased by 25% find

vaieri [72.5K]

Answer:75lbs

Step-by-step explanation:

1/4 of 60lbs is 15. add 15 to 60 to get 75. hope this helps

5 0

3 years ago

PLEASEEEE HELP!!!!! I WILL MAKE BRAINLEST!!!!!!!!!!!! What's the common difference of 1,3,5,8

Llana [10]

Answer:

There is no common difference

Step-by-step explanation:

7 0

3 years ago

What is the tangent ratio for angle f?

ValentinkaMS [17]

Answer:

your answer is 8/6

Step-by-step explanation:

the equation for tangent is opposite side/adjacent side but you cant use the hypotenuse which is 10 so you end up with the opposite side 8 and the adjacent side 6 so the final answer comes to 8/6

5 0

3 years ago

18+2x100= ??? help plz

Mandarinka [93]

Answer:

218

Step-by-step explanation:

help me on my recent

8 0

3 years ago

Read 2 more answers

The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth

Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

(c) The probability that at least three of the selected computers are desktops is 0.401.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = $P(Laptop) = p_{X} = \frac{4}{9}$

The probability of selecting a desktop is = $P(Desktop) = p_{Y} = \frac{5}{9}$

Then both X and Y follows Binomial distribution.

$X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})$

The probability function of a binomial distribution is:

$P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}$

(a)

Combination is used to determine the number of ways to select k objects from n distinct objects without replacement.

It is denotes as: ${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

${8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70$

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

$P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\ =0.304832\\\approx0.305$

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

$P(Y\geq 3)=1-P(Y$

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0

3 years ago