There are 32,760 different orders for the first four positions.
This is a permutation where repetition is not allowed; the formula for that is:

For our problem, we have:
Answer:
-3
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given:
∠DCE ≅ ∠DEC
∠B ≅ ∠F
DF ≅ BD
To prove:
ΔABC ≅ ΔGFE
Solution:
Statements Reasons
1). ∠DCE ≅ ∠DEC 1). Given
2). ∠ACB ≅ ∠GEF 2). Vertically opposite angles to the
congruent angles.
3). ∠B ≅ ∠F 3). Given
4). DB ≅ DF 4). Given
5). DC + CB ≅ DE + EF 5). Segment addition postulate
6). DC ≅ DE 6). Property of isosceles triangle
7). CB ≅ EF 7). Transitive property
8). ΔABC ≅ ΔGFE 8). ASA property of congruence