Question

Toxic Pollution: In the first year of a study, health officials discovered toxic pollutants in the soil surrounding a factory. The initial measurement was 65 parts per million (ppm) of pollutant. They returned to take similar measurements for several years afterward, and uncovered a disturbing trend. The pollutant levels in the soil surrounding the factory were growing exponentially, at a rate of 4.5% each year. Which exponential model predicts the amount of pollutant in the soil t years from the first measurement?

Answer 1

Answer:

The model for the pollutant levels in the soil t years from the first measurement is:

$Y(t)=65e^{0.044}$

Step-by-step explanation:

We have a first measurement of 65 parts per million (ppm) of pollutant.

We also know that the pollutant levels were growing exponentially at a rate of 4.5% a year.

We can model this as:

$Y(t)=Y_0e^{kt}$

The value of Y0 is the first measurement, that correspond to t=0.

$Y_0=65$

The ratio for the pollutant levels for two consecutive years is 1+0.045=1.045. This can be expressed as the division between Y(t+1) and Y(t), and gives us this equation:

$\dfrac{Y(t+1)}{Y(t)}=\dfrac{Y_0e^{k(t+1)}}{Y_0e^{kt}} =\dfrac{e^{k(t+1)}}{e^{kt}}=e^{k(t+1-t)}=e^k=1.045\\\\\\k=ln(1.045)\approx 0.044$

Then, we have the model for the pollutant levels in the soil t years from the first measurement:

$Y(t)=65e^{0.044}$