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mestny [16]
3 years ago
11

HELPPPPPPPPPPPPPPPPPPPPPP

Mathematics
2 answers:
Helga [31]3 years ago
6 0
To solve this let us try to get x on it's own in the inequality.

-6<3x-12<=9
6<3x<=21
2<x<=7

Now a filled dot indicates <= or >= and empty indicates < or > so we know that the answer must have a filled dot on 7 and an empty dot on 2, with a line in between.

The answer is B, the selected one.
Kay [80]3 years ago
4 0
The answer to your problem would be answer B
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Step-by-step explanation:

When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative

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Geometry math question no Guessing and Please show work
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ArbitrLikvidat [17]

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Step-by-step explanation:

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3 years ago
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If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°
Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

8 0
3 years ago
What is the measure of
kondaur [170]
Edit your question so we know what you are asking
8 0
3 years ago
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