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Ad libitum [116K]
4 years ago
14

What's the answer ?????

Mathematics
1 answer:
Mamont248 [21]4 years ago
4 0
Your answer is correct
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A circle has a radius of 4 x^3 y^5 cm. The area of a circle can be found using A equals pi r^2
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Answer:

Step-by-step explanation:

There are two other important distances on a circle, the radius (r) and the diameter (d). The radius, the diameter, and the circumference are the three defining aspects of every circle. Given the radius or diameter and pi you can calculate the circumference. The diameter is the distance from one side of the circle to the other at its widest points. The diameter will always pass through the center of the circle. The radius is half of this distance. You can also think of the radius as the distance between the center of the circle and its edge.

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4 years ago
If f(x) =
givi [52]

Answer:

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8 0
3 years ago
Please help asap, will mark Brainliest xoxo
IgorC [24]

Answer/Step-by-step explanation:

Given, b(x) = (\frac{6}{7})^{x}

The table for the function are:

When x = -2

b(-2) = (\frac{6}{7})^{-2}

b(-2) = \frac{1}{(\frac{6}{7})^{2}}

b(-2) = \frac{1}{(\frac{36}{49})}

b(-2) = 1*\frac{49}{36}

b(-2) = \frac{49}{36}

When x = -1

b(-1) = (\frac{6}{7})^{-1}

b(-1) = \frac{1}{(\frac{6}{7})}

b(-1) = 1*\frac{7}{6}

b(-2) = \frac{7}{6}

When x = 0

b(0) = (\frac{6}{7})^{0}

b(0) = \frac{6^0}{7^0}

b(0) = \frac{1}{1}

b(0) = 1

When x = 1

b(1) = (\frac{6}{7})^{1}

b(1) = \frac{6}{7}

When x = 2

b(2) = (\frac{6}{7})^{2}

b(2) = \frac{6^2}{7^2}

b(2) = \frac{36}{49}

3 0
4 years ago
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