I believe the answer is A. 20, 30, 40 is NOT a pythagorean triple.
Yes cause he can decrease the perimeter in any way and it would change the area and idk the other 2 in the front
Answer:
2x^2*(2x^3+8x^2+2x) or
4x^5+16x^4+4x^3
Step-by-step explanation:
A=[2x^3-x+(8x^2+3x)]*4x^2/2=2x^2*(2x^3+8x^2+2x)
or A=4x^5+16x^4+4x^3
Step-by-step explanation:
ans is 23 please mark me as brainlist please