Question

Please help! find the equation (in terms of x) of the line through the point (-4,3) and (3,-2)

Answer 1

Answer: y= -5/7 x + 1/7

Step-by-step explanation:

Answer 2

Answer:

$y=-\frac{5}{7} x+\frac{1}{7}$

Step-by-step explanation:

Equation of a line: $y = mx+b$

m is the slope, and b is the y-intercept.

m = $\frac{rise}{run} =\frac{y_{2}-y_{1} }{x_{2}-x_{1} } = \frac{-2-3}{3-(-4)} =-\frac{5}{7}$

Now, we have $y=-\frac{5}{7} x+b$

We can insert one set of points in to solve for b.

We will use the first point (-4, 3):

$3=-\frac{5}{7} (-4)+b$

$\frac{5}{7}* \:4+b=3$

$\frac{20}{7}+b=3$

$b=\frac{1}{7}$.

Equation:$y=-\frac{5}{7} x+\frac{1}{7}$