3 years ago

Consider the graph of the quadratic function y = 3x2 – 3x – 6.

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

3 0

Answer:

(-1, 2 )

Step-by-step explanation:

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Tomtit [17]

Answer:

2.5

Step-by-step explanation:

5x+3x=20

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3 years ago

Find the area of the triangle. Enter your answer in the box.

BlackZzzverrR [31]

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Explanation:

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2 years ago

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ladessa [460]

Answer:

Let S = starting point

Let ST = length of tunnel

SR = 1414 m

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Set up:

ST^2 + SR^2 = RT^2

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Step-by-step explanation:

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2 years ago

Which equation is graphed in the picture.<br><br> PLEASE HELP!!!!!

Fynjy0 [20]

Answer:

2x + 3y = 6

Step-by-step explanation:

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3 years ago

<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2

guapka [62]

Step-by-step explanation:

$\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)$

Use the identity

$\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}$

on the left side.

$\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)$

$\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)$

Now use the identity

$\sin \theta = \cos(\frac{\pi}{2} - \theta)$

on the left side.

$\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)$

$\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)$

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2 years ago