Answer:
Assuming that the scale is 1, x int: (-4,0), y int: (0,-3)
Step-by-step explanation:
Hope this helps :)
Answer:
Ques 11: 123.08 meters.
Ques 12: 269.4 meters.
Ques 13: 211.27 meters.
Step-by-step explanation:
Ques 11: We have that the angle of elevation from the ship to the top of the lighthouse is 18° and the height of the lighthouse is 40 m.
It is required to find the distance of the ship from the shore, say 'x' m.
As, we have, ![\tan \theta=\frac{opposite}{adjacent}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%3D%5Cfrac%7Bopposite%7D%7Badjacent%7D)
⇒ ![\tan 18=\frac{40}{x}](https://tex.z-dn.net/?f=%5Ctan%2018%3D%5Cfrac%7B40%7D%7Bx%7D)
⇒ ![x=\frac{40}{\tan 18}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B40%7D%7B%5Ctan%2018%7D)
⇒ ![x=\frac{40}{0.325}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B40%7D%7B0.325%7D)
⇒ x = 123.08 m.
Thus, the distance of the ship from the shore is 123.08 meters.
Ques 12: We have, length of the kite is 300 m and the angle made by the string is 64°.
It is required to find the height of the kite, say 'x' m.
As, we have, ![\sin\theta=\frac{opposite}{hypotenuse}](https://tex.z-dn.net/?f=%5Csin%5Ctheta%3D%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D)
⇒ ![\sin 64=\frac{x}{300}](https://tex.z-dn.net/?f=%5Csin%2064%3D%5Cfrac%7Bx%7D%7B300%7D)
⇒ ![x=300\times \sin 64](https://tex.z-dn.net/?f=x%3D300%5Ctimes%20%5Csin%2064)
⇒ ![x=300\times 0.898](https://tex.z-dn.net/?f=x%3D300%5Ctimes%200.898)
⇒ x = 269.4 m.
Hence, the height of the kite is 269.4 meters.
Ques 13: We have, the wreckage is found at the angle of 12° and the diver is lowered down by 45 meters.
It is required to find the distance covered by the diver to reach the wreckage, say 'x' m.
As, we have, ![\tan \theta=\frac{opposite}{adjacent}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%3D%5Cfrac%7Bopposite%7D%7Badjacent%7D)
⇒ ![\tan 12=\frac{45}{x}](https://tex.z-dn.net/?f=%5Ctan%2012%3D%5Cfrac%7B45%7D%7Bx%7D)
⇒ ![x=\frac{45}{\tan 12}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B45%7D%7B%5Ctan%2012%7D)
⇒ ![x=\frac{45}{0.213}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B45%7D%7B0.213%7D)
⇒ x = 211.27 m.
Thus, the distance covered by the diver to reach the wreckage is 211.27 meters.
V=1/3*πr² *h,
raduus r=32/2=16
V=1/3*3.14*(16)² *18=6*3.14*(16)² =4823.04
Answer:
It's 48 degrease
Step-by-step explanation:
Both of the other angles are the same which means that the other two are gonna be the same.
The answer is C just guessed and i got it right.