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3 years ago

HELP PLEASE!!!! OFFERING POINTS!

Mathematics

2 answers:

levacccp [35]3 years ago

7 0

Answer:

Step-by-step explanation:

Solve for x

- 4 (x - 2) = - 4 There are a a couple of ways of doing this. Divide by - 4

-4 (x - 2)/-4 = - 4/-4 Combine

x - 2 = 1 Add 2

x = 3

Solve for y

9 + 2(y - 3) = 3(y - 2) + 1 Remove the brackets on both sides.

9 + 2y - 6 = 3y - 6 + 1 Combine

9 - 6 + 2y = 3y - 5

3 + 2y = 3y - 5 Add 5

3 + 5 + 2y = 3y Subtract 2y

8 + 2y - 2y = 3y - 2y

8 = y

Solve for z

z/3 + 1/2 = 5/2 Subtract 1/2 from both sides.

z/3 + 1/2 - 1/2 = 5/2 - 1/2 Combine

z/3 = 4/2

z/3 = 2 Multiply by 3

z/3*3 = 2*3

z = 6

So far what you have is

8 || 6

== must = 4 because 3 + 8 + 4 = 15

|| must = 1 because 8 + 6 + 1 = 15

You have 3 numbers left to place 5,7,2

The right hand upper corner = 7.

I'll leave you to place the 5 and 2

Aloiza [94]3 years ago

3 0

Answer:

find the missing numbers

Step-by-step explanation:

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3 years ago

Read 2 more answers

A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t

Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be $F=L+2W$ .

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

$LW=80,000...(1)$

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be $C=20L+5(2W)\Rightarrow 20L+10W$ .

From equation (1), we will get:

$L=\frac{80,000}{W}$

Upon substituting this value in cost equation, we will get:

$C=20(\frac{80,000}{W})+10W$

$C=\frac{1600,000}{W}+10W$

$C=1600,000W^{-1}+10W$

To minimize the cost, we need to find critical points of the the derivative of cost function as:

$C'=-1600,000W^{-2}+10$

$-1600,000W^{-2}+10=0$

$-1600,000W^{-2}=-10$

$-\frac{1600,000}{W^2}=-10$

$-10W^2=-1,600,000$

$W^2=160,000$

$\sqrt{W^2}=\pm\sqrt{160,000}$

$W=\pm 400$

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

$C''=-2(-1600,000)W^{-3}$

$C''=3200,000W^{-3}$

$C''=\frac{3200,000}{W^3}$

Now, we will substitute $W=400$ in 2nd derivative as:

$C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05$

Since 2nd derivative is positive at $W=400$ , therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting $W=400$ in $L=\frac{80,000}{W}$ , we will get:

$L=\frac{80,000}{400}\\\\L=200$

Therefore, the side parallel to the river will be 200 feet.

4 0

3 years ago

Solve for x ‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎ ‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎ ‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎ ‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎

Pie

Answer:

18.46

Step-by-step explanation:

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2 years ago

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kondor19780726 [428]

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Ivahew [28]

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The image has the following measurements:
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height = 4 inches

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2 years ago