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Over [174]
3 years ago
14

The appalachian trail is about 2175 miles long if katia averages 18 miles each day how long will it take her to hike the length

of the trail
Mathematics
1 answer:
sladkih [1.3K]3 years ago
7 0

Answer:


Step-by-step explanation:

Katia's speed is 18 miles per day.

Distance is 2175. Time taken is Distance/speed

2175/18 days is the time taken = 120 days ,19 hours, 59 minutes 24 seconds


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Information about the proportion of a sample that agrees with a certain statement is given below. Use StatKey or other technolog
lorasvet [3.4K]

Answer:

a) Standard Error = 0.010

b) 95% Confidence Interval = (0.0924 , 0.1316)

Step-by-step explanation:

a) The formula for Standard Error = √Sample Proportion (1 - sample proportion)/n

Standard Error = √p (1 - p)/n

We are told in the question that:

In a random sample of 400 people, 112 agree and 288 disagree. Estimate the standard error using 1000 samples

p = x/n

n = 1000 because we were told to use it instead of 400

x = number for people that agree = 112

p = 112/1000

p = 0.112

Standard Error = √p (1 - p)/n

= √0.112 (1 - 0.112)/1000

= √0.112 × 0.888/1000

= √0.099456 /1000

= √0.000099456

= 0.0099727629

Approximately to 3 decimal places = 0.010

Therefore, the standard error is 0.010

b) The Question above also asked that we solve for the 95% Confidence Interval

The formula =

p ± z × Standard Error

p = 0.112

z score for 95% confidence interval = 1.96

Standard Error = 0.010

Confidence Interval =

0.112 ± 1.96 × 0.010

= 0.112 ± 0.0196

0.112 - 0.0196

= 0.0924

0.112 + 0.0196

0.1316

Therefore, the 95% confidence interval = (0.0924 , 0.1316)

8 0
3 years ago
Read 2 more answers
The average weight of a midsize car is 1 3/4 tons. The average weight of a compact car is 6/7 of the weight of a midsize car. Ho
Alborosie
6/7 of 1 3/4......turn the mixed number to an improper fraction...and " of " means multiply
6/7 * 7/4 = 42/28 = 1 1/2...so a compact car weighs 1 1/2 tons or 1.5 tons
7 0
3 years ago
I need help on my math test!
Strike441 [17]

Answer:  the answer should be c

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Major league baseball salaries averaged $1.5 million with a standard deviation of $0.8 million in 1994. suppose a sample of 100
seropon [69]

Answer: The probability that the avg. salary of the 100 players exceeded $1 million is approximately 1.

Explanation:

Step 1: Estimate the standard error. Standard error can be calcualted by dividing the standard deviation by the square root of the sample size:

SE=\frac{0.8}{\sqrt{100}}=\frac{0.8}{10} = 0.08

So, Standard Error is 0.08 million or $80,000.

Step 2: Next, estimate the mean is how many standard errors below the population mean $1 million.

\frac{1 - 1.5}{0.08}

=-6.250

-6.250 means that $1 million is siz standard errors away from the mean. Since, the value is too far from the bell-shaped normal distribution curve that nearly 100% of the values are greater than it.

Therefore, we can say that because 100% values are greater than it, probability that the avg. salary of the 100 players exceeded $1 million is approximately 1.

5 0
3 years ago
How you do you solve for it??
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