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ale4655 [162]
3 years ago
14

Assume the readings on thermometers are normally distributed with a mean of degrees and a standard deviation of 1.00degrees. Fin

d the probability that a randomly selected thermometer reads greater than negative 0.69 and draw a sketch of the region.

Mathematics
1 answer:
Valentin [98]3 years ago
3 0

Answer:

Hence, the probability that randomly selected thermometer reads greater than negative 0.69 is 0.7549

Step-by-step explanation:

Consider the provided information.

The readings on thermometers are normally distributed with a mean of degrees and a standard deviation of 1.00 degrees.

That means the value of σ = 1.

We need to find the probability that a randomly selected thermometer reads greater than negative 0.69

That means the value of mean is 0.

Normal distribution = z=\frac{x-\mu}{\sigma}

Substitute the respective values as shown:

The probability should be greater that -0.6, Thus.

P(X>-0.6)=\frac{-0.69-0}{1}=-0.69

Now use the standard normal table to find the value of P(Z>-0.69)

P(X>-0.6)=0.7549

Hence, the probability that randomly selected thermometer reads greater than negative 0.69 is 0.7549

The required region is shown in figure 1.

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The probability that all of the next ten customers who want this racket can get the version they want from current stock is 0.821

<h3>How to solve?</h3>

Given: currently has seven rackets of each version.

Then the probability that the next ten customers get the racket they want is P(3≤X≤7)

<h3>Why P(3≤X≤7)?</h3>

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X ~ Binomial (n = 10, p = 0.6)

P(3≤X≤7)  = P(X≤7) - P(X≤2)

From Binomial Table:

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               = 0.821

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6 0
2 years ago
Jim Tree sells trees. The mean length of the trees purchased was 68 inches with a standard deviation of 10 inches. Jim wants to
Zepler [3.9K]

Step-by-step explanation:

We know that,

Z=\dfrac{X-\mu}{\sigma}

Where,

X = raw score = 84

μ = mean = 68

σ = standard deviation = 10

Putting the values,

Z=\dfrac{84-68}{10}=1.6

The percent of his sales that were less than or equal to 84 inches, is

P(Z\leq 1.6)=0.9452=94.52\%\approx 94.5\%

Therefore, the remaining 100-94.5=5.5% were more than 84 inches.

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3 years ago
I bought 8 shirts that cost an average of $27. My sister then added 3 shirts. The 11 shirts had a mean cost of 28.50. How much d
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It cost 50 cent each  first i subtracted 27 from 28.50 and it gave me 1.50 de i divided 1.50 by 3 and it gave 50 cent

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