Your inequality is (x being number of people):
175≥35+10x+3x
First, combine like terms so your new inequality is:
175≥35+13x
Then subtract 35 from both sides which makes it:
140≥13x
then divide 140 by 13 making it:
<span>10.769≥x
</span>But because you can't have .769 of a person the actual answer is 10
then you have to subtract 1 because he isn't including himself and there is the answer!:
9≥x
The best way to put them into a number line is to make sure that they've all got the same denominator, which in this case, will be 24, as this is the lowest common multiple of 3,4 and 8. You will then need to multiply these fractions accordingly. The first one (1/4) will need to be multiplied by 6 to get a denominator of 24, so this will then give you a result of 6/24. The second one (2/3), will need to be multiplied by 8, which will then give you a result of 16/24. The third one (3/4)will also need to be multiplied by 6, giving you 18/24. The final one (6/8) will need to be multiplied by 3, giving you 18/24. You will then need to put these in order, which will be- 1/4, 2/3, 3/4, and 6/8.
The alternative method is to turn these into decimals- 1/4 is equivalent to 25%, which is equal to 0.25. 2/3 is equivalent to 66.66%, which is equivalent to 0.66. 3/4 is equivalent to 75%, which is equal to 0.75. 6/8 is also equivalent to 75%, which is equal to 0.75, you can then easily line them up this way.
Hope this has been able to help you
Answer:
p - w = $25 OR w + $25 = p
Step-by-step explanation:
pencil = p
pen = w
p - w = $25 OR w + $25 = p
Answer:
408.2sq inches
Step-by-step explanation:
Area of the cylindrical box = 2πr(r+h)
r is the radius = diameter/2
r = 10/2 = 5in
h is the height = 8in
Substitute
Area of the cylindrical box = 2(3.14)(5)(5+8)
Area of the cylindrical box = 2 * 3.14 * 5 * 13
Area of the cylindrical box = 408.2sq inches
Answer:
I will attach the missing drawing with the answer.
9.b)
Plane JKM
Plane JLM
Plane KLM
Step-by-step explanation:
The drawing for this question is missing. I will attach it with the answer.
9.a) Plane JKL is not an appropriate name for the plane because all of three points lie in the same line.
Through a line pass infinite planes. The plane JKL doesn't define a unique plane. That's why plane JKL isn't an appropriate name for the plane.
9.b) We can name the plane using three points that don't lie in the same line.
Three possible names for the plane are :
Plane JKM
Plane JLM
Plane KLM
