It’s 27 because u multiple the first 2 number and it’s a negative then add the rest to it
<span>y=−3x+2</span> is a linear equation in slope-intercept form with
slope <span>m=<span>(−3)</span></span>
(and y-intercept <span>=2</span>)
We want the equation of a line with slope <span>m=<span>(−3)</span></span> through the point <span>(<span>−2</span>,<span>−8</span>)</span>
Using the point-slope linear equation form:
<span><span>(y−<span>(−8)</span>)</span>=<span>(−3)</span><span>(x−<span>(−2)</span>)</span></span>
Simplifying
<span>y+8=−3x−6</span>
or, in standard form
<span>3x+y=−<span>14</span></span>
Answer:
See below
Step-by-step explanation:
13*1 = 13
13*2 = 26
13*3 = 39
13*4 = 52
13*5 = 65
13*6 = 78
13*7 = 91
13*8 = 104
13*9 = 117
13*10 = 130
Answer:
C
Step-by-step explanation:
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude and n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)
The correct answer is option D. y = 2 sin (θ/2)
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<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude and n = 2π/period
<span>amplitude = 5 , period = 2π/n = 2π/2 = π
</span>
The correct answer is option B. Period: pi radians: Amplitude:5
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3. tan (2π/3) = tan 120° = -√3
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3
The correct answer is C. -sqrt3
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4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3
The correct answer is <span>B.-sqrt3/3</span>
