The gcf of any two odd numbers is always odd
1 answer:
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<h3>Answer: C) 12</h3>
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Explanation:
Refer to the diagram below. I'm using the points A,B,C,D,E to help label the triangles, and to label the angles as well.
For now, let's focus on triangle DEC.
The top most angle is given as D = 65. Note how the angles D and E are opposite the congruent lines (marked with the red single tickmarks). This means that angles D and E are congruent to one another. So E = 65 as well. This is shown in the diagram below.
For now we don't know what angle C is, so we'll call it y. More specifically, we'll make y the measure of angle DCE.
For any triangle, the three angles always add to 180
y+65+65 = 180
y+130 = 180
y = 180-130
y = 50
So angle DCE is 50 degrees.
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Now we move onto triangle ABC.
Because angles DCE and ACB are vertical angles, this makes angle ACB 50 degrees also. Effectively, anywhere you see a 'y' in the diagram below, replace it with 50.
So triangle ABC has the three angles y = 50, y = 50 and 7x-4
We can solve for x like so
y+y+(7x-4) = 180
50+50+(7x-4) = 180
7x+96 = 180
7x = 180-96
7x = 84
x = 84/7
x = 12
This points to choice C as the final answer.
Answer:
a. a = 1, b = -5, c = -14
b. a = 1, b = -6, c = 9
c. a = -1, b = -1, c = -3
d. a = 1, b = 0, c = -1
e. a = 1, b = 0, c = -3
Step-by-step explanation:
a. x-ints at 7 and -2
this means that our quadratic equation must factor to:
FOIL:
Simplify:
a = 1, b = -5, c = -14
b. one x-int at 3
this means that the equation will factor to:
FOIL:
Simplify:
a = 1, b = -6, c = 9
c. no x-int and negative y must be less than 0
This means that our vertex must be below the x-axis and our parabola must point down
There are many equations for this, but one could be:
a = -1, b = -1, c = -3
d. one positive x-int, one negative x-int
We can use any x-intercepts, so let's just use -1 and 1
The equation will factor to:
This is a perfect square
FOIL:
a = 1, b = 0, c = -1
e. x-int at
our equation will factor to:
This is also a perfect square
FOIL and you will get:
a = 1, b = 0, c = -3