When adding two rational

Find 0.1 more than a number and 0.1 less than a number. Find 0.01 more than a number and 0.01 less than a number. Find 0.001 mor

viktelen [127]

Answer:

Okay so our number in this example is going to be 23 because it is my favorite.

So you start of by saying okay

23+0.1

and that would equal 23.1

and then you would think

23-0.1

and that would equal 22.9

and then you would do the same thing just move a place

so 23+0.001

and that would equal 23.001

and then you subtract it

so 23-0.001

and that would equal 22.999

hope this helped :)

6 0

1 year ago

A direct variation function contains the points (–9, –3) and (–12, –4). Which equation represents the function?

katen-ka-za [31]

Answer:

$\displaystyle y = \frac{1}{3}x$

Step-by-step explanation:

First, find the rate of change [slope]:

$\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{3 - 4}{9 - 12} = \frac{1}{3}$

Then plug these coordinates into the Slope-Intercept Formula instead of the Point-Slope Formula since you get it done much swiftly that way. It does not matter which ordered pair you choose:

−4 = ⅓[−12] + b

−4

$\displaystyle ±0 = b \\ \\ y = \frac{1}{3}x$

_______________________________________________

−3 = ⅓[−9] + b

−3

$\displaystyle ±0 = b \\ \\ y = \frac{1}{3}x$

**You see? I told you it did not matter which ordered pair you choose because you will ALWAYS get the exact same result.

I am joyous to assist you anytime.

8 0

3 years ago

Read 2 more answers

The circumference of a circle is 7pi ft. Find its diameter in feet

Mumz [18]

Answer:

The diameter is 7 ft.

Step-by-step explanation:

Circumference= Diameter*pi

5 0

4 years ago

Read 2 more answers

Simplify the expression.

Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

6 0

4 years ago

Can someone help me with both questions I will mark u brilliant

allsm [11]

1. First, he will be climbing 10,000 feet from where he is right now. 10,000 / 1,000 = 10.

-3.6 x 10 = 36 degree decrease.

25 - 36 = -11

At 12,000 feet, the temperature will be -11.

2. First, we need to do 8.80 x 7 = 61.6

61.6 / 4 = 15.4

61.6 - 15.4 = 46.2

He has $26.20 left.

Hope this helps!

4 0

2 years ago