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3 years ago

If 5x + 32 =4-2x, what is the value of x ?

2 answers:

5 0

5x + 32 = 4- 2x
Add 2x to both sides to get 7x + 32 = 4
Subtract 32 from both sides to get 7x = -28
Divide both sides by 7 to get x = -4
Hope this helps :)

Ket [755]3 years ago

3 0

Hi there!

To solve this problem, we need to simplify.

5x + 32 = 4 - 2x
7x + 32 = 4
7x = -28

x = -4

Hope this helps!

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A study done by researchers at a university concluded that % of all student athletes in this country have been subjected to som

Nostrana [21]

The missing digits is highlighted in bold form

A study done by researchers at a university concluded that 70% of all student-athletes in this country have been subjected to some form of hazing. The study is based on responses from 1800 athletes. What are the margin of error and 95% confidence interval for the study?

Answer:

Step-by-step explanation:

Given that:

The sample proportion $\hat p = 0.70$

The sample size n = 1800

At 95% confidence interval level:

The level of significance = 1 - 0.95 = 0.05

Critical value: $Z_{0.05/2} = Z_{0.025} = 1.96$

Thus, the Margin of Error E = $Z_{\alpha/2} \times \sqrt{\dfrac{\hat p ( 1- \hat p)}{n}}$

$= 1.96 \times \sqrt{\dfrac{ 0.70 ( 1-0.70)}{1800}}$

$= 1.96 \times \sqrt{\dfrac{ 0.70 ( 0.30)}{1800}}$

$= 1.96 \times \sqrt{\dfrac{0.21}{1800}}$

$= 1.96 \times \sqrt{1.16666667\times 10^{-4}}$

the Margin of Error E = 0.021

At 95% C.I for the population proportion will be:

$= \hat p \pm Z_{\alpha/2} \sqrt{\dfrac{\hat p(1- \hat p)}{n}}$

= 0.70 ± 0.021

= (0.70 - 0.021, 0.70 + 0.021)

= 0.679, 0.721)

6 0

3 years ago

What is the value of h in the figure below? In this diagram, ABAD ~ ACBD.

bazaltina [42]

Answer:

is it A and C ):

Step-by-step explanation:

8 0

3 years ago

Please please help me out with this problem

Hatshy [7]

Answer:

y = 3x - 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line

m = $\frac{2+4}{2-0}$ = $\frac{6}{2}$ = 3

Note the line crosses the y- axis at (0, - 4) ⇒ c = - 4

y = 3x - 4 ← equation of line

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4 years ago

What is the maximum safe angle of elevation for the resuce ladder

bazaltina [42]

65.4(degrees)

X=100'

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3 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

3 years ago