The missing digits is highlighted in bold form
A study done by researchers at a university concluded that 70% of all student-athletes in this country have been subjected to some form of hazing. The study is based on responses from 1800 athletes. What are the margin of error and 95% confidence interval for the study?
Answer:
Step-by-step explanation:
Given that:
The sample proportion 
The sample size n = 1800
At 95% confidence interval level:
The level of significance = 1 - 0.95 = 0.05
Critical value: 
Thus, the Margin of Error E = 




the Margin of Error E = 0.021
At 95% C.I for the population proportion will be:

= 0.70 ± 0.021
= (0.70 - 0.021, 0.70 + 0.021)
= 0.679, 0.721)
Answer:
is it A and C ):
Step-by-step explanation:
Answer:
y = 3x - 4
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line
m =
=
= 3
Note the line crosses the y- axis at (0, - 4) ⇒ c = - 4
y = 3x - 4 ← equation of line
65.4(degrees)
X=100'
I think
Answer:
0.1994 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 166 pounds
Standard Deviation, σ = 5.3 pounds
Sample size, n = 20
We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling =

P(sample of 20 boxers is more than 167 pounds)
Calculation the value from standard normal z table, we have,
0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds