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jolli1 [7]
3 years ago
9

Nolan plots a point at (0, 3) on the y-axis. He uses a slope of 2 to graph another point. He draws a line through the two points

. Which equation represents Nolan’s line?
Mathematics
1 answer:
Soloha48 [4]3 years ago
3 0
Equation of a line passing through a point is given by: (y - y1)/(x - x1) = m. where m is the slope.
Hence, we have
(y - 3)/x = 2
y - 3 = 2x
y = 2x + 3
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nexus9112 [7]

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consumer math / answer is A

Step-by-step explanation:

3 0
3 years ago
in the second half of the game, the Wildcats again scored 18 points. This time, however, we don't know how many total shots were
Kobotan [32]

Lets start with the chain of 3's:

18 = 3 + 3 + 3 + 3 + 3 + 3          

But, we know that

3 + 3 = 2 + 2 + 2

Sol, let's replace 3 + 3 by 2 + 2 + 2 one by one.

Hence, the possible ways of combinations are listed below:

18 = 3 + 3 + 3 + 3 + 2 + 2 + 2                        (1)

18 = 3 + 3 + 2 + 2 + 2 + 2 + 2 + 2                  (2)

Therefore, there are two combinations of 2- and 3- point shots that could total 18 points.

3 0
3 years ago
Help i dont know what it is if i get one more wrong i dont pass the level
Semenov [28]

Answer:

blue and green because parallel means two lines that will never cross

3 0
2 years ago
The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?
MAXImum [283]
<span>f(k) = k2 + 2k + 1 = (k+1)^2
The range is what the function gives to you f(k)=25=5^2 or (-5)^2
f(k)=64=8^2 or (-8)^2

You need to find the k values for these boundary values to find the domain. 
Good luck :)</span>
7 0
3 years ago
Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.
disa [49]

Answer:

The solutions x^4-5x^2-36=0 are x=3,\:x=-3,\:x=2i,\:x=-2i and the x-intercepts of y=x^4-5x^2-36 are x=3,\:x=-3

Step-by-step explanation:

Finding the solutions to x^4-5x^2-36 means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with u=x^2 and u^2=x^4

u^2-5u-36=0

Solve by factoring

\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)

\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)

\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)

u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)

\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)

u^2-5u-36=\left(u+4\right)\left(u-9\right)=0

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

\:u=-4,\:u=9

Substitute back u=x^2, solve for x

x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)

Apply the difference of squares formula

x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)

(x-3)(x+3)(x^2+4)=0

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

\:x=3,\:x=-3,\:x=2i,\:x=-2i

Because two of the solutions are complex roots the only x-intercepts are x=3,\:x=-3

3 0
3 years ago
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