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disa [49]
3 years ago
12

We’re doing similarity and I’m really confused

Mathematics
2 answers:
Drupady [299]3 years ago
5 0

Answer:

Hello its ok Love!

I believe x = 2 hope this helps good luck!

Komok [63]3 years ago
3 0

Answer: 2 ft

Step-by-step explanation:

18 / 4.5 = 4

8 / 4 = 2

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Fill in the blank and with &gt; &lt; or = to make the statement true <br> 5/8 ____ 1/4
Eva8 [605]

Answer:

5/8 > 1/4

Step-by-step explanation:

4 0
3 years ago
Evaluate: (9/64)^1/2
Anna [14]

Answer:

\frac{3}{8}

Step-by-step explanation:

Using the rules of exponents

(a^m)^{n} = a^{mn}

a^{\frac{1}{2} } = \sqrt{a}

Hence

\frac{9^{\frac{1}{2} } }{64^{\frac{1}{2} } }

= \frac{\sqrt{9} }{\sqrt{64} } = \frac{3}{8}

3 0
2 years ago
Read 2 more answers
3.432, 1.283, -2.7, 1.483, 2.263 least to greatest
zmey [24]

Answer:

-2.7, 1.283, 1.483, 2.263, 3.432 hope this helps

4 0
3 years ago
Read 2 more answers
What is the following quotient? StartFraction 6 minus 3 (RootIndex 3 StartRoot 6 EndRoot) Over RootIndex 3 StartRoot 9 EndRoot E
Bezzdna [24]

Exponent properties help us to simplify the powers of expressions.  The quotient of the given expression \dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}} is (2∛3 - ∛18).

<h3>What are the basic exponent properties?</h3>

{a^m} \cdot {a^n} = a^{(m+n)}\\\\\dfrac{a^m}{a^n} = a^{(m-n)}\\\\\sqrt[m]{a^n} = a^{\frac{n}{m}}\\\\(a^m)^n = a^{m\times n}\\\\(m\times n)^a = m^a\times n^a\\\\

Given to us

\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}

We will solve the problem using the basic exponential properties,

\dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}}\\\\ = \dfrac{6}{\sqrt[3]{9}} - \dfrac{3(\sqrt[3]{6})}{\sqrt[3]{9}}\\\\ = (6\cdot 3^{-\frac{2}{3}}) - [3 \cdot (2 \cdot 3)^{-\frac{2}{3}}3^{-\frac{2}{3}}]\\\\= (2 \cdot 3 \cdot 3^{-\frac{2}{3}}) - [3 \cdot 2^{-\frac{2}{3}} \cdot 3^{-\frac{2}{3}}3^{-\frac{2}{3}}]\\\\

= [2 \cdot 3^{(1-\frac{2}{3})}] - [2^{\frac{1}{3}}\cdot 3^{(1+\frac{1}{3} - \frac{2}{3})}]\\\\=  [2 \cdot 3^{(\frac{1}{3})}] - [2^{\frac{1}{3}}\cdot 3^{(\frac{2}{3})}]\\\\= 2\sqrt[3]{3} - \sqrt[3]{2}\sqrt[3]{9}\\\\=2\sqrt[3]{3} - \sqrt[3]{18}

Hence, the quotient of the given expression \dfrac{6 - 3(\sqrt[3]{6})}{\sqrt[3]{9}} is (2∛3 - ∛18).

Learn more about Exponents:

brainly.com/question/5497425

4 0
2 years ago
Clare estimates that her brother is 4 feet tall. When they get measured at the doctor's office,
avanturin [10]

Answer:

2 inches

Step-by-step explanation:

Since his actual height was 4 feet and 2 inches, instead of the estimate of 4 feet, the difference was 2 inches.

This means the error in inches was also 2 inches, since the estimated height was 2 inches lower than the one at the doctor's office.

So, the error is 2 inches

5 0
2 years ago
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