Answer:si amigos si adorqa nueve tres dies=z cien bien se hasta luego
Answer:
Between 21 years and 75 years
Step-by-step explanation:
Given that a real estate company is interested in the ages of home buyers. They examined the ages of thousands of home buyers and found that the mean age was 48 years old, with a standard deviation of 9 years.
X the ages of home buyers is N(48, 9)
a) 
Hence using Cheby chev inequality

b) 

c) Using normal distribution we have

d) z value is 2.97
Hence x lies between

Between 21 years and 75 years
Answer:
d The product of a constant factor of seven and a factor with the sum of two terms
Step-by-step explanation:
It's a product, and one of the factors is 7.
Answer:
d The product of a constant factor of seven and a factor with the sum of two terms
Answer:- 29
false
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
Simplify left and right parts separately.
<u>Left part:</u>

<u>Right part:</u>

Since simplified left and right parts are the same, then the equality is true.