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3 years ago

9

Find an equation of the line passing through the point (-7,-5) that is perpendicular to the line y=5/3x-5

2 answers:

alexdok [17]3 years ago

8 0

Y=-3/5x-46/5 or y=-3/5x-9 1/5

Orlov [11]3 years ago

7 0

Answer:

y= -3/5x - 46/5

Step-by-step explanation:

Since the line is perpendicular to y=5/3x-5, We can find the gradient since perpendicular lines have negative reciprocal gradients of each other, so in this case the gradient of the line is -3/5. We have a point, we have the gradient, so we can substitute in y=mx+c to find the y-intercept c, so -5 = (-3/5)(-7) + c.

Calculating will give c= -46/5

so the equation is y= (-3/5)x + (-46/5)

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