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Arturiano [62]
3 years ago
14

A fish tank contains tetras,guppies,and minnows. The ratio of tetras of guppies.Is 4:2.The ratio is minnows of guppies is 1:3. T

here are 60 fish on the fish tank. How many more tetras are there then minnows .
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

30

Step-by-step explanation:

Let number of tetras be "t"

number of guppies be "g"

number of minnows be "m"

Ratio of tetras to guppies is 4:2, or reducing, 2:1. Thus we can write:

\frac{t}{g}=\frac{2}{1}\\t=2g

Ratio of minnows to guppies is 1:3, so we can write:

\frac{m}{g}=\frac{1}{3}\\g=3m

or, m = g/3

Also, total there are 60 fish, so we can write:

t + g + m = 60

or

2g + g + g/3 = 60

Solving this, we can solve for g. Shown below:

2g+g+\frac{g}{3}=60\\3g+\frac{g}{3}=60\\\frac{9g+g}{3}=60\\10g=180\\g=18

Now, finding t and m:

m = g/3 = 18/3 = 6

m = 6

and

t = 2g

t = 2(18)

t= 36

There are 36 tetras and 6 minnows. So, there are

36 - 6 = 30 more tetras than minnows

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3 years ago
A sample of n = 4 scores is obtained from a population with a mean of 70 and a standard deviation of 8. If the sample mean corre
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Answer:

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Step-by-step explanation:

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Also, the sample mean corresponds to a z score of 2.00.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for a sample mean is given by;

              Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = 70

            \sigma = standard deviation = 8

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The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, we are given that the sample mean corresponds to a z score of 2.00 for which we have to find the value of sample mean;</u>

So, <em><u>z-score</u></em> formula is given by ;

                  z-score = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } = \frac{\bar X-70}{\frac{8}{\sqrt{4} } }

                      2.00 =  \frac{\bar X-70}{\frac{8}{\sqrt{4} } }

                      2.00 =  \frac{\bar X-70}{4 } }

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                     \bar X = 70 + 8 = 78

<em>Therefore, the value of the sample mean is 78.</em>

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