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Arturiano [62]
3 years ago
14

A fish tank contains tetras,guppies,and minnows. The ratio of tetras of guppies.Is 4:2.The ratio is minnows of guppies is 1:3. T

here are 60 fish on the fish tank. How many more tetras are there then minnows .
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

30

Step-by-step explanation:

Let number of tetras be "t"

number of guppies be "g"

number of minnows be "m"

Ratio of tetras to guppies is 4:2, or reducing, 2:1. Thus we can write:

\frac{t}{g}=\frac{2}{1}\\t=2g

Ratio of minnows to guppies is 1:3, so we can write:

\frac{m}{g}=\frac{1}{3}\\g=3m

or, m = g/3

Also, total there are 60 fish, so we can write:

t + g + m = 60

or

2g + g + g/3 = 60

Solving this, we can solve for g. Shown below:

2g+g+\frac{g}{3}=60\\3g+\frac{g}{3}=60\\\frac{9g+g}{3}=60\\10g=180\\g=18

Now, finding t and m:

m = g/3 = 18/3 = 6

m = 6

and

t = 2g

t = 2(18)

t= 36

There are 36 tetras and 6 minnows. So, there are

36 - 6 = 30 more tetras than minnows

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t-value = 2.441

Step-by-step explanation:

Let's assume that this is a one-tailed test to calculate the critical value, the process is this:

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