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Semenov [28]
3 years ago
6

Mrs Richmond bought some apples and pears in the ratio 2:5. An apple costs 30 cents. A pear costs 15 cents mire than an apple. H

ow much did mrs richmond pay for the fruit
Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

$2.85

Step-by-step explanation:

30×2=60

30+15=45

60+(45×5)=?

45×5=225

60+225=285

$2.85

Cuz every 100cents is one dollar

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The measure of an exterior angle of a triangle is always_____.
Blababa [14]

Answer:

The measure of an exterior angle of a triangle is always greater than the measure of either of the opposite interior angles of the triangle

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2 years ago
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If the area A of a triangle is 60sq m (square meters) and the base b is 20m (meters) what is the altitude of h
umka2103 [35]

Answer:

<u>The altitude or height of the triangle is 6 meters.</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Area of a triangle = 60 m²

Base = 20 m

2. What is the altitude (h) of the triangle?

Let's recall that the formula of the area of a triangle is:

Area = (Base * Height)/2

Replacing with the real values, we have:

60 = (20 * Height)/2

60 * 2 = (20 * Height) (Multiplying by 2 at both sides)

120 = 20 Height

Height = 120/20 = 6 meters

<u>The altitude or height of the triangle is 6 meters.</u>

8 0
3 years ago
If bob earns 35,000 a month how much does he earn in 2 years and 75 weeks
nlexa [21]
Okay, do 35,000x24=840,000
840,000/104=8,077
8077x75=605,769
605,769+840,000=1,445,769.23
:-)
6 0
3 years ago
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College Calculus - hyperbolic functions (see attachment)
morpeh [17]

Answer:

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

Step-by-step explanation:

Using the fundamental theorem of calculus

Taking the derivative of the integral gives back the function

Since the lower limit is a constant when we take the derivative it is zero

d/dx \int\limits^x_4 {g(t)} \, dt  = g(x)

g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))

Replacing t with x

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

6 0
3 years ago
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timama [110]

Looks like your function is

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Rewrite it as

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Recall that for |x|, we have

\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n

If we replace x with -6x^2, we get

f(x)=\displaystyle x\sum_{n=0}^\infty\frac(-6x^2)^n=\sum_{n=0}^\infty (-6)^n x^{2n+1}

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Solving for x gives the interval of convergence,

|x|^2

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3 0
3 years ago
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