Question

A sample of ????=25 diners at a local restaurant had a mean lunch bill of $16 with a standard deviation of ????=$4 . We obtain a 95% confidence interval as (14.43,17.57) . Which action will not reduce the margin of error?

Answer 1

Answer:

"Decreasing the sample size."

Step-by-step explanation:

The margin of error is :

$ME=z\times \frac{\sigma }{\sqrt{n}}$

Therefore, as n decreases, margin of error increases.

In the question we are asked " Which action will not reduce the margin of error."

Therefore, the correct option for which action will not reduce the margin of error is "Decreasing the sample size."