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2 years ago

What were the conditions in Jewish ghettos under Nazi rule?

Mathematics

1 answer:

nasty-shy [4]2 years ago

7 0

Answer:

Conditions in the ghettos were appalling. For example, the majority of the apartments in the Warsaw ghetto were unheated during winter, and the Nazis decided that the inhabitants of the Warsaw ghetto could survive on an official food allocation of 300 calories per day (compared with 634 calories for the Poles and 2,310 for the Germans).

The Nazis ordered Jews to wear identifying badges or armbands with a yellow Star of David on them in the ghettos. Many Jews were also required to perform forced labor for the German Reich. The Nazi-appointed Jewish councils (Judenrat) and Jewish police maintained order within the ghettos and were forced by the Germans to facilitate deportations to the extermination camps.

Step-by-step explanation:

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Plz help me this one is a lil tough

Aneli [31]

Answer:

100 degrees

Step-by-step explanation:

It's going through 140 and 40, 180 - 40 = 140

180 cause a flat line is 180 degrees

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3 years ago

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Please help me solve this ;-;

Digiron [165]

9514 1404 393

Answer:

C log3(√((x -4)/x)

Step-by-step explanation:

The applicable rules of logarithms are ...

log(a/b) = log(a) -log(b)

log(a^n) = n·log(a)

The base is irrelevant, as long as all logs are to the same base.

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2 years ago

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Trava [24]

June :
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900 + .02(50,200) + 0.018(50200 - 17500) =
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2 years ago

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Solve the equation x^2-18x+21=-3x to the nearest tenth

pav-90 [236]

Answer:

x=1.6 and x=13.4

Step-by-step explanation:

First we must bring -3x over to the left side by addin git the both sides

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1 year ago

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When do we use the addition and subtraction formulas for sine or cosine?

777dan777 [17]

When we need the cosine of the sum of two angles, we use the addition formula for cosine.

When we need the sine of the difference of two angles, we use the difference formula for sine.

Let's try one. Say we needed to know

$\cos 15^\circ
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We're only expected to know the trig functions of 30/60/90 and 45/45/90 triangles. Fortunately, $15^\circ = 45^\circ - 30^\circ$ so

$\cos 15^\circ = \cos( 45^\circ - 30^\circ )$

$= \cos( 45^\circ) \cos(30^\circ ) + \sin(45^\circ) \sin(30^\circ)$

$= \dfrac{\sqrt{2}}{2} \cdot \dfrac{ \sqrt{3}}{2} + \dfrac{\sqrt{2}}{2} \cdot \dfrac{1}{2}$

$\cos 15^\circ = \frac{1}{4} (\sqrt{6} + \sqrt{2})$

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2 years ago