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Tanzania [10]
3 years ago
11

Create an equation to solve for x using the trapezoid midsegment formula:

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

Equation for x:    3x - 6 = \frac{2x - 1 + 25}{2}

x = 9

CD = 17

GH = 21

Step-by-step explanation:

The midsegment formula for a trapezoid is

GH = \frac{CD + FE}{2}

3x - 6 = \frac{2x - 1 + 25}{2}

6x - 12 = 2x + 24

4x = 36

x = 9

CD = 2x - 1 = 2(9) - 1 = 18 - 1 = 17

GH = 3x - 6 = 3(9) - 6 = 3 = 27 - 6 = 21

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Temka [501]

The rectangular equation for given parametric equations x = 2sin(t) and   y = -3cos(t) on 0 ≤ t ≤ π is  \frac{x^{2} }{4} +\frac{y^2}{9} =1 which is an ellipse.

For given question,

We have been given a pair of parametric equations x = 2sin(t) and           y = -3cos(t) on 0 ≤ t ≤ π.

We need to convert given parametric equations to a rectangular equation and sketch the curve.

Given parametric equations can be written as,

x/2 = sin(t) and y/(-3) = cos(t) on 0 ≤ t ≤ π.

We know that the trigonometric identity,

sin²t + cos²t = 1

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⇒ \frac{x^{2} }{4} +\frac{y^2}{9} =1

This represents an ellipse with center (0, 0), major axis 18 units and minor axis 8 units.

The rectangular equation is  \frac{x^{2} }{4} +\frac{y^2}{9} =1

The graph of the rectangular equation \frac{x^{2} }{4} +\frac{y^2}{9} =1 is as shown below.

Therefore, the rectangular equation for given parametric equations x = 2sint and y = -3cost on 0 ≤ t ≤ π is  \frac{x^{2} }{4} +\frac{y^2}{9} =1 which is an ellipse.

Learn more about the parametric equations here:

brainly.com/question/14289251

#SPJ4

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