Answer: ![sds\\ \\ x^{2} \geq \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n \geq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. x^{2} \lim_{n \to \infty} a_n \pi \neq \sqrt{x} \neq](https://tex.z-dn.net/?f=sds%5C%5C%20%5C%5C%20x%5E%7B2%7D%20%5Cgeq%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cgeq%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%5Cpi%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20x%5E%7B2%7D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cpi%20%5Cneq%20%5Csqrt%7Bx%7D%20%5Cneq)
Step-by-step explanation:i need the think points
Answer:
0.013
0.031
0.03
0.1
I hope my answer's correct.
Step-by-step explanation:
B. <span>–4.37 < –1.63 is the true statement. -4.37 is less than -1.63
</span>
A. <span>–4.28 > –3.56 * should be less than
</span>C. <span>5.7 < 5.63 * should be greater than
</span>D. -13.90 > 4.63 *should be less than
In dealing with negative numbers, the greater the negative number is, the lesser its value. 4.37 is a greater number than 1.63 in its positive form, however, its negative form give 4.37 a lesser value than 1.63 in its negative form.
